Answer:
I can't draw a picture but its possible cuz they painted ABOUT 1/5 of the bird house so Jane could have painted a bit more than 1/5 but it would still be about 1/5
Answer:
-8
Step-by-step explanation:
plz watch all steps in picture
Supposing, for the sake of illustration, that the mean is 31.2 and the std. dev. is 1.9.
This probability can be calculated by finding z-scores and their corresponding areas under the std. normal curve.
34 in - 31.2 in
The area under this curve to the left of z = -------------------- = 1.47 (for 34 in)
1.9
32 in - 31.2 in
and that to the left of 32 in is z = ---------------------- = 0.421
1.9
Know how to use a table of z-scores to find these two areas? If not, let me know and I'll go over that with you.
My TI-83 calculator provided the following result:
normalcdf(32, 34, 31.2, 1.9) = 0.267 (answer to this sample problem)
Answer:
The correct option is;
3 + (-9) = -6, because -6 is 9 units to the left of 3
Step-by-step explanation:
The given information are;
Kelvin's score after the first round is shown at point K on the number line
The range of numbers on the number line = -10 to +10
The position of point K after the first round = +3
The number of points Kevin lost in the second round = 9 points
Therefore, Kevin's cumulative score = +3 - 9 = -6
Therefore, the expression that shows how many total points he has at the end is of round 2 = 3 + (-9) = -6, because -6 is 9 units to the left of 3.
