Is 16% of 40 the same as 40% of 16
1 answer:
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Hi There!
Change all the fractions to decimal you do that by dividing numerator by the denominator. Remember
as a decimal is 0.5
A=
= 0.43
B=
= 0.60
C=
= 0.8
D=
= 0.42
E=
= 0.6
Based, on the data above B,C,E are greater than because they all have decimals greater than 0.5, B= 0.6, C= 0.8, E=0.6
So,
are all greater than
Hope This Helps :)
Change all the fractions to decimal you do that by dividing numerator by the denominator. Remember
A=
B=
C=
D=
E=
Based, on the data above B,C,E are greater than
So,
Hope This Helps :)
Answer: option d. x = 3π/2
Solution:
function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).
Solution:
function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).
