You take the length times the width to get the area.
I'll solve it algebraically
x+y=4
x-3y=12
multiply first equatoin by -1 and add to second
-x-y=-4
<u>x-3y=12 +</u>
0x-4y=8
-4y=8
divide both sides by -4
y=-2
sub back
x+y=4
x+-2=4
add 2 to both sides
x=6
x=6
y=-2
(6,-2)
Answer:
0.07
Step-by-step explanation:
Answer:
red area = 7.74 in^2
Step-by-step explanation:
area of square = 6x6 = 36
radius = 1/2 diameter, radius = 3
area of circle = (3.14)(3^2) = 28.26
36-28.26 = 7.74
The acceptable first step in simplifying the expression
is (a) 
The expression is given as:

To change the form of the expression, we simply perform several arithmetic operations on it.
Start by multiplying the expression by 1/1

Express 1 /1 as (1 - sec x)/(1 - sec x)

Rewrite the above expression as follows:

Hence, the acceptable first step is (a)
Read more about trigonometry ratios at:
brainly.com/question/24888715