If 870mg is 30% of recommended daily amount, then we can set up the equation:
870 = 0.30 * x (where x is the recommended amount)
870 / 0.3 = x
x = 2900mg
Therefore the recommended daily amount is 2900mg of salt
The quotient of 58÷8 is: 7.25
Quotient is just another work for divide my friend.
Answer:
See below
Step-by-step explanation:
There are two ways to graph an equation.
<u>1st Way:</u>
We can use a graphing calculator. (See the attached file)
<u>2nd Way:</u>
We can take the values of x as 0, 1 , 2 (Or anything).
Then, We have to put the values of x in the equation to get the value of y accordingly.
According to these values, Plot the graph.
Also,
Slope = 5 / 6
y-intercept = 1
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
The numbers -4 and 4 have a sum of zero.
Why?
-4 + 4 = 0.
4 + -4 = 0.
<em><u>Any Questions? Comment Below!</u></em>
<u><em>-AnonymousGiantsFan</em></u>
Answer:
![x = \frac{\sqrt 3}{ 3}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B%5Csqrt%203%7D%7B%203%7D)
Step-by-step explanation:
Given
See attachment for complete question
First, we calculate the water pipe length (AC):
![AC^2 = AB^2 + BC^2](https://tex.z-dn.net/?f=AC%5E2%20%3D%20AB%5E2%20%2B%20BC%5E2)
![AC^2 = 1^2 + x^2](https://tex.z-dn.net/?f=AC%5E2%20%3D%201%5E2%20%2B%20x%5E2)
![AC^2 = 1 + x^2](https://tex.z-dn.net/?f=AC%5E2%20%3D%201%20%2B%20x%5E2)
![AC = \sqrt{1 + x^2](https://tex.z-dn.net/?f=AC%20%3D%20%5Csqrt%7B1%20%2B%20x%5E2)
The cost of laying across water is twice (2 times) laying on land.
So, the total cost (C) is:
![C = 2 * \sqrt{1 + x^2} + 1 * (4 - x)](https://tex.z-dn.net/?f=C%20%3D%202%20%2A%20%5Csqrt%7B1%20%2B%20x%5E2%7D%20%2B%201%20%2A%20%284%20-%20x%29)
![C = 2 \sqrt{1 + x^2} + (4 - x)](https://tex.z-dn.net/?f=C%20%3D%202%20%5Csqrt%7B1%20%2B%20x%5E2%7D%20%2B%20%284%20-%20x%29)
Differentiate
![C' = \frac{2x}{\sqrt{1 + x^2}} - 1](https://tex.z-dn.net/?f=C%27%20%3D%20%5Cfrac%7B2x%7D%7B%5Csqrt%7B1%20%2B%20x%5E2%7D%7D%20-%201)
To find the most economical cost, we simply minimize C' by equating C' to 0
![C' = 0](https://tex.z-dn.net/?f=C%27%20%3D%200)
![\frac{2x}{ \sqrt{1 + x^2}}-1 = 0\\](https://tex.z-dn.net/?f=%5Cfrac%7B2x%7D%7B%20%5Csqrt%7B1%20%2B%20x%5E2%7D%7D-1%20%3D%200%5C%5C)
![\frac{2x}{ \sqrt{1 + x^2}}=1](https://tex.z-dn.net/?f=%5Cfrac%7B2x%7D%7B%20%5Csqrt%7B1%20%2B%20x%5E2%7D%7D%3D1)
Cross multiply
![2x= \sqrt{1 + x^2}](https://tex.z-dn.net/?f=2x%3D%20%5Csqrt%7B1%20%2B%20x%5E2%7D)
Take square of both sides
![4x^2 = 1+x^2](https://tex.z-dn.net/?f=4x%5E2%20%3D%201%2Bx%5E2)
Collect like terms
![4x^2 -x^2= 1](https://tex.z-dn.net/?f=4x%5E2%20-x%5E2%3D%201)
![3x^2= 1](https://tex.z-dn.net/?f=3x%5E2%3D%201)
Solve for ![x^2](https://tex.z-dn.net/?f=x%5E2)
![x^2 = \frac{1}{3}](https://tex.z-dn.net/?f=x%5E2%20%3D%20%5Cfrac%7B1%7D%7B3%7D)
Solve for x
![x = \sqrt{\frac{1}{3}}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![x = \frac{1}{\sqrt 3}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%203%7D)
Rationalize:
![x = \frac{1}{\sqrt 3} * \frac{\sqrt 3}{\sqrt 3}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%203%7D%20%2A%20%5Cfrac%7B%5Csqrt%203%7D%7B%5Csqrt%203%7D)
![x = \frac{\sqrt 3}{ 3}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B%5Csqrt%203%7D%7B%203%7D)