Solution;
The gas is at STP;
Where; T = 273 K , P = 1 atm
We know that 1 mole of a gas at STP occupies a volume of 22.4 liters .
V1/n1 = V2/n2
n2 = (V2/V1) n1
n2 = (2 l/22.4 l)(1 mole)
n2 = 0.0893 moles
But 1 mole of a compound has 6.022 × 10^23 molecules
Thus, number of molecules = 0.0893 moles × 6.022 ×10^23 molecules
= 5.378 × 10^22 molecules.
Answer:
Li-F
Explanation:
Hydroxide is a negative ion, which can form ionic bonds with metals, but the bond in hydrogen and oxygen in hydroxide (OH-) is not ionic. It is covalent in nature.
C-C is clearly a covalent bond.
Li-F is an ionic bond.
Bond between H and Cl in H-Cl is covalent in nature. Because of the size difference hydrogen can not act as a cation. So it rather dissociates.
Answer:
0.5ppm
Explanation:
Step 1:
Data obtained from the question.
Volume of water = 2500L
Mas of Cu = 1.25 g
Step 2:
Determination of the concentration of Cu in g/L. This is illustrated below:
Volume of water = 2500L
Mas of Cu = 1.25 g
Conc. of Cu In g/L =?
Conc. g/L = Mass /volume
Conc. of Cu in g/L = 1.25/2500
Conc. of Cu in g/L = 5x10^–4 g/L
Step 3:
Conversion of the concentration of Cu in g/L to ppm. This is illustrated below
Recall:
1g/L = 1000mg/L
Therefore, 5x10^–4 g/L = 5x10^–4 x 1000 = 0.5mg/L
Now, we know that 1mg/L is equal to 1ppm.
Therefore, 0.5mg/L is equivalent to 0.5ppm
The answer is c. An insulator does not conduct heat.
HC₂H₃O₂ , equilibrium can be represented as:
HC₂H₃O₂ + H₂O--------->CH₃COO⁻ + H₃O⁺
HC₂H₃O₂, that is acetic acid dissociate in water that is H₂O and formed acetate anion that is CH₃COO⁻ and hydronium ions that is H₃O⁺.
Its equiibrium constant can be represented as:
Ka=\frac{[CH_{3}COO^{-1}]\times [H_{3}O^{+1}]}{CH_{3}COOH}
While NaC₂H₃O₂ can be dissociate as:
NaC₂H₃O₂------>CH₃COO⁻ + Na⁺
Sodium acetate that is NaC₂H₃O₂, dissociates as forming acetate anion and sodium cation.
