1. find our slope: y2 - y1/ x2- x 1
-9 + 4= -5
2 - 2 = 0
m = 0
2. now we need to use our point-slope form to find our y intercept
point-slope form: y - y1 = m(x - x1)
y + 4 = 0(x - 2)
distribute:
y + 4 = 0x
3. get y by itself
y + 4 - 4 = y
0x - 4 = 0x - 4
4. write in slope-intercept form:
y = 0x - 4
OR
y = -4
Step-by-step explanation:
The volume of a cylinder can be found with the equation
<em><u>
</u></em>
So, plug in the values. The diameter of the circle is 10m, which means that the radius is 5m. The height of the cylinder is 13m.
V = π (5)^2 (13)
<u>V = 325π m^3</u>
Answer:
D. 325π m^3
Use slope formula: y2-y1/x2-x1
XZ: -5/9
YZ: 2/7
XY: -7/2
XYZ is a right triangle because two of these slopes have a product of -1.
(YZ and XY does). We are all busy these days.
Answer:
<h2>$128847</h2>
Step-by-step explanation:
given Principle at 31250
and rate = 12%
and time 12.5 years
the amount would be given by the equation
plug in values to get
end up with value $128847
The maximum height the ball achieves before landing is 682.276 meters at t = 0.
<h3>What are maxima and minima?</h3>
Maxima and minima of a function are the extreme within the range, in other words, the maximum value of a function at a certain point is called maxima and the minimum value of a function at a certain point is called minima.
We have a function:
h(t) = -4.9t² + 682.276
Which represents the ball's height h at time t seconds.
To find the maximum height first find the first derivative of the function and equate it to zero
h'(t) = -9.8t = 0
t = 0
Find second derivative:
h''(t) = -9.8
At t = 0; h''(0) < 0 which means at t = 0 the function will be maximum.
Maximum height at t = 0:
h(0) = 682.276 meters
Thus, the maximum height the ball achieves before landing is 682.276 meters at t = 0.
Learn more about the maxima and minima here:
brainly.com/question/6422517
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