To Find :
How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% antifreeze.
Solution :
Let, x gallons of 80% antifreeze solution is required :
So,

Therefore, 500 gallons of 80% antifreeze solution is required.
The solution is y < -1/5
In order to find the answer to this problem, follow the order of operations for solving equations/inequalities.
444 + 555y < 333 -----> Subtract 444 from both sides
555y < -111 -----> Divide both sides by 555
y < -1/5
30 degrees of the circle which is an acute angle.
8.95, that's not including the possible tax