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3 years ago

Which relationship has a zero slope?

Mathematics

1 answer:

Ivenika [448]3 years ago

6 0

9514 1404 393

Answer:

A. A two column table with five rows. The first column, x, has the entries, negative 3, negative 1, 1, 3. The second column, y, has the entries, 2, 2, 2, 2

Step-by-step explanation:

The relationship that has constant y-values is the one with zero slope. That would be the first table.

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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

IgorC [24]

Answer:

$9.99\text{secs}$

Explanation:

Here, we want to find the time the rocket will hit the ground

What we have to do is to substitute 0 for the height of the rocket y and solve the quadratic equation that results

That simply means we are solving for:

$0=-16x^2+149x+108$

We can use the quadratic formula to solve this

$x\text{ = }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

where a is the coefficient of x^2 which is -16

b is the coefficient of x which is 149

c is the last number which is 108

Substituting the values, we have it that:

$\begin{gathered} x\text{ = }\frac{-149\pm\sqrt[]{149^2-4(-16)(108)}}{2(-16)} \\ \\ x\text{ = }\frac{-149\pm\sqrt[]{29113}}{-32}\text{ } \\ \\ x\text{ = }\frac{-149-170.625\text{ }}{-32} \\ or\text{ } \\ x\text{ = }\frac{-149_{}+170.625}{-32} \end{gathered}$

Now, we proceed to get the individual x-values: