10.2 in. x + 4 in. x + 4 in. n x + 4 in. x + 4 in. 10.2 in.

What does the ratio pi represent in any circle?

Hoochie [10]

The number pi is a constant, it's the ratio of a circles circumference to it's diameter.

5 0

3 years ago

Last year, sales at Company X were 10% greater in February than in January, 15% less in March than in Feb, 20% greater in April

horsena [70]

Answer:

May

Step-by-step explanation:

Let x be the sales in January,

∵ Sales were 10% greater in February than in January,

So, the sales in February = (100 +10)% of x

= 110% of x

= $\frac{110x}{100}$

= 1.1x

∵ it is 15% less in March than in Feb,

Sales in march = (100-15)% sales in February

= 85% of 1.1x

= 0.935x

∵ It is 20% greater in April than in March,

Sales in April = (100+20)% of sales in march

= 120% of 0.935x

= 1.122x,

∵ It is 10% less in May than in April

Sales in May = (100-10)% of sales in march

= 90% of 1.122x,

= 1.0098x,

∵ It is 5% greater in June than in May

Sales in June = (100+5)% of sales in march

= 105% of 1.0098x,

= 1.5147x

∵ 1.0098x is much closure to x than 1.1x, 0.935x, 1.122x and 1.5147x

Hence, the sales in May is closest to sales in January.

6 0

4 years ago

A particle moves along line segments from the origin to the points (2, 0, 0), (2, 4, 1), (0, 4, 1), and back to the origin under

Shkiper50 [21]

The work is equal to the line integral of $\vec F$ over each line segment.

Parameterize the paths

from (0, 0, 0) to (2, 0, 0) by $\vec r_1(t)=t\,\vec\imath$ with $0\le t\le2$ ,
from (2, 0, 0) to (2, 4, 1) by $\vec r_2(t)=2\,\vec\imath+4t\,\vec\jmath+t\,\vec k$ with $0\le t\le1$ ,
from (2, 4, 1) to (0, 4, 1) by $\vec r_3(t)=(2-t)\,\vec\imath+4\,\vec\jmath+\vec k$ with $0\le t\le2$ , and
from (0, 4, 1) to (0, 0, 0) by $\vec r_4(t)=(4-4t)\,\vec\jmath+(1-t)\,\vec k$ with $0\le t\le1$

The work done by $\vec F$ over each segment (call them $C_1,\ldots,C_4$ ) is

$\displaystyle\int_{C_1}\vec F\cdot\mathrm d\vec r_1=\int_0^2\vec0\cdot\vec\imath\,\mathrm dt=0$

$\displaystyle\int_{C_2}\vec F\cdot\mathrm d\vec r_2=\int_0^1(t^2\,\vec\imath+24t\,\vec\jmath+32t^2\,\vec k)\cdot(4\,\vec\jmath+\vec k)\,\mathrm dt=\int_0^1(96t+32t^2)\,\mathrm dt=\frac{176}3$

$\displaystyle\int_{C_3}\vec F\cdot\mathrm d\vec r_3=\int_0^2(\vec\imath+(24-12t)\,\vec\jmath+32\,\vec k)\cdot(-\vec\imath)\,\mathrm dr=-\int_0^2\mathrm dt=-2$

$\displaystyle\int_{C_4}\vec F\cdot\mathrm d\vec r_4=\int_0^1((1-t)^2\,\vec\imath+2(4-4t)^2\,\vec k)\cdot(-4\,\vec\jmath-\vec k)\,\mathrm dt=-2\int_0^1(4-4t)^2\,\mathrm dt=-\frac{32}3$

Then the total work done by $\vec F$ over the particle's path is 46.

8 0

4 years ago

Some one help ts also says explain ur thinking

AysviL [449]

Answer:

Step-by-step explanation:

Start off by explaining that u know this(don't use these exact word though :A composite number is a positive integer that can be formed by multiplying two smaller positive integers Equivalently. A prime number is a natural number greater than 1 that is not a product of two smaller natural numbers.... I couldn't really see the whole page so this is what i could get for u.... Good luck

7 0

3 years ago

Which expression is the simplest form of -(2x+y)+3(x-4y)?

Maru [420]

Answer:

x-13y

Step-by-step explanation:

Combine like terms and when you do x is by itself and you have 13 y

making the answer x-13y

8 0

3 years ago