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nataly862011 [7]
3 years ago
6

I really need help with this it's super hard for me.​

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
7 0

Answer:

c

f

d

a

b

e

Step-by-step explanation:

f(3)=2×3+5= 11

g(0)=-1/3 ×0 +2 =2

f(1)=2×1+5=7 and so on. :)

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5 pounds of avacado a costs $9 what is the cost for 1 pound of avacados
STALIN [3.7K]

Answer:


Step-by-step explanation:

9/5= 1.8

$1.80 per lb

6 0
4 years ago
Read 2 more answers
PLEASE HELP!!!! THIS LINEAR EQUATIONS!!!
melomori [17]
The answer is C,
120x + 60y \geqslant 600
We use the 'more than or equal sign' as the consultant needs to make at least $600 - so exactly $600 or more than $600
4 0
3 years ago
At a restaurant, three salads, two sandwiches, and one drink cost $17.75. One salad, one sandwich, and three drinks cost $10.75.
Leno4ka [110]

Answer:

A salad costs $2.50

A sandwich costs $4.50

A drink costs $1.25

Step-by-step explanation:

Let x represent the salad, y represent the sandwich, and z represent the drink.

Since three salads, two sandwiches, and one drink cost $17.75:

3x + 2y + z = 17.75  (1)

Since one salad, one sandwich, and three drinks cost $10.75:

x + y + 3z = 10.75  (2)

Since a salad costs twice as much as a drink:

x = 2z  (3)

Multiply the equation 2 by -2 then, sum the equation 1 and equation 2:

-2x - 2y - 6z = -21.50

3x + 2y + z = 17.75

→ x - 5z = -3.75

Replace the x with 2z using equation 3:

2z - 5z = -3.75

-3z = -3.75

z = 1.25

x = 2z → x = 2.50

x + y + 3z = 10.75 → 2.50 + y + 3.75 = 10.75 → y + 6.25 = 10.75 → y = 4.50

5 0
3 years ago
When comparing two box-plots that show the same type of information, what determines agreement within the data?
Mice21 [21]

Answer:

c.the mean of each data set

5 0
3 years ago
Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0
3 years ago
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