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nataly862011 [7]
3 years ago
6

I really need help with this it's super hard for me.​

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
7 0

Answer:

c

f

d

a

b

e

Step-by-step explanation:

f(3)=2×3+5= 11

g(0)=-1/3 ×0 +2 =2

f(1)=2×1+5=7 and so on. :)

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Match each exponential expression with its value
Paha777 [63]
Here’s the answers
have a nice day

4 0
3 years ago
During the first hour of operation the farm stand owner sold 15% of the apples he had. On the second hour he sold 20% of the rem
liraira [26]

Answer:

 3.825 kg apples.

Step-by-step explanation:

Let x kg be the amount of apples stand owner had initially.

We have been given that during the first hour of operation the farm stand owner sold 15% of the apples he had. Then the amount of sold apples will be:

\text{The amount of sold apples during 1st hour}=\frac{15}{100}x=0.15x

\text{The amount of remaining apples after 1st hour}=x-0.15x

\text{The amount of remaining apples after 1st hour}=0.85x

On the second hour he sold 20% of the remaining apples. So the amount of sold apples on the second hour will be 20% of 0.85x.

\text{The amount of sold apples during 2nd hour}=0.85x*\frac{20}{100}  

\text{The amount of sold apples during 2nd hour}=0.85x\times 0.20  

\text{The amount of sold apples during 2nd hour}=0.17x

During the second hour 25.5 kg of apples were sold, so we can set up an equation as:

25.5=0.17x

\frac{25.5}{0.17}=\frac{0.17x}{0.17}

150=x

So, stand owner had initially 150 kg of apples.

\text{The amount of remaining apples after 2nd hour}=0.85x-0.17x

\text{The amount of remaining apples after 2nd hour}=0.68x

On the third hour he sold 25% of the remaining apples. So the amount of sold apples on the 3rd hour will be 25% of 0.68x

\text{The amount of sold apples during 3rd hour}=0.68x*\frac{25}{100}

\text{The amount of sold apples during 3rd hour}=0.68x*0.25

\text{The amount of sold apples during 3rd hour}=0.17x  

\text{The amount of remaining apples after 3rd hour}=0.68x-0.17x

\text{The amount of remaining apples after 3rd hour}=0.51x

As remaining apples were sold 5% more each following hour.

\text{The amount of sold apples during 4th hour}=0.51x*\frac{5}{100}

\text{The amount of sold apples during 4th hour}=0.51x*0.05

\text{The amount of sold apples during 4th hour}=0.0255x

Let us substitute x=150 into above equation we will get,

\text{The amount of sold apples during 4th hour}=0.0255*150

\text{The amount of sold apples during 4th hour}=3.825

Therefore, 3.825 kg of apples were sold during the 4th hour.

7 0
3 years ago
Fill in the blank (Geometry B)
liubo4ka [24]

Step-by-step explanation:

ratio

to

sind = d/e

sinf = f/e

8 0
2 years ago
When g ( t ) = 3 t 2 + 2 t + 1 , evaluate g ( − 4 )
Luda [366]

Answer:

Just substitue every 't' with -4

Step-by-step explanation:

g(-4) = 3*(-4)*(-4) + 2*(-4) + 1

g(-4) = 64-8+1

g(-4) = 57

7 0
3 years ago
Read 2 more answers
I need the answer please don’t scam with a link
-BARSIC- [3]
A.) False
b.) True
c.) True
d.) True
3 0
3 years ago
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