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3 years ago

Multiply, (x+4)(x-4) simplify answer.

Mathematics

2 answers:

Ulleksa [173]3 years ago

8 0

I think it is:

(x+4)(x-4)
x(x-4)+4(x-4)
x2-4x+4x-16
x2-16
????????????

trasher [3.6K]3 years ago

3 0

That's the easily recognizable factored form of
the difference between two squares. Before
factoring, it was

x² - 16 .

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an owl travels 8 1/3 miles an hour and a seagull travels 12 1/2 miles in 2/3 hour. which animal is faster?

Simora [160]

Seagull because the owl has 5 5/9 and the sea 8 1/3

5 0

3 years ago

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Solve for x : 6x+ 1/4 (4x+8)> 12

loris [4]

Answer:

x > 10/7 or x > 1 3/7

Step-by-step explanation:

First simplify the left side of the inequality.

6x+ 1/4 (4x+8)> 12

6x+x+2>12

7x+2>12 Next, using the property of inequality, subtract two from both sides.

7x>10 Now divide by 7 to solve for x.

x>10/7 or x> 1 3/7

6 0

3 years ago

Six machines, each working at the same constant rate, together can complete a certain job in 12 days. How many additional machin

Schach [20]

Answer:

3 machine

Step-by-step explanation:

It is given that 6 machine each working at the same rate can complete the work in 12 days

We the has to complete in 8 days

Let we need x extra machine to complete the work in 8 days

So total number of machines =x+6

Now according to man work day equation $M_1D_1=M_2D_2$

$6\times 12=(x+6)\times 8$

$8x+48=72$

$8x=24$

x=3 machine

7 0

3 years ago

How do you go about doing this surface area problem?

hammer [34]

Break it down into 2-Dimensional shapes. Then add the areas together.

From the picture you can see;
front & back rectangles are 2*(4 x 8) = 64 m²
2 side rectangles are 2*(4 x 12) = 56 m²
2 triangular front & back pieces are (1/2)*8*3 = 12 m²
2 roof rectangles are 2*(5 x 12) = 120 m²

total Surface area = 64 m² + 56 m² + 12 m² + 120 m²
= 252 m²

For the volume; break it up into 3-dimenssional shapes and add the volumes together.

From the picture you can see;
Rectangular box volume is 4 x 8 x 12 = 384 m³
Triangular roof volume is area of front triangle multiplied through the length. (1/2)*8*3* 12 = 144 m³

Total volume = 384 m³ + 144 m³
= 528 m³

5 0

3 years ago

What is the sum or difference?

dlinn [17]

1. Ans: Option (B) $-6x^4$

Explanation:
Given: $2x^4 - 8x^4$
Take the common out:
=> $x^4(2 - 8)$

Hence: => $[tex]-6x^4$ [/tex] (Option B)

2. Ans: Option (D) $-3y^5$

Explanation:
Given: $6y^5 - 9y^5$
Take the common term(s) out:
=> $y^5(6-9)$

Hence: => $-3y^5$ (Option D)

3. Ans: Option (B) $9x^2 - 12x + 6$ quadratic trinomial

Explanation:
Given: $6 - 12x + 13x^2 - 4x^2$

The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.

=> $13x^2 - 4x^2 - 12x + 6$
=> $9x^2 - 12x + 6$ (Option B)

4. Ans: Option (C) $7.3x^2 + 0.8x + 1.3$

Explanation:
In order to find the total number of Common and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:

Common guppies: $3.1x^2 +6.0x + 0.3$ 
Endler's guppies: $4.2x^2 - 5.2x + 1.0$
(add both)
-----------------------------------------------------------------
Total number: $7.3x^2 +0.8x + 1.3$
-----------------------------------------------------------------
Hence the ans is Option(C) $7.3x^2 + 0.8x + 1.3$

5. Ans: Option (D) $2x^2(133 - 18 \pi )$

Explanation:
First let's find the total area of the yard:
Total Area of the Yard = 14x * 19x = $266x^2$

Now the area of the circular fountain:
Area of the Circular Fountain = $\pi r^2$
Since, r=6x
Therefore,
Area of the Circular Fountain = $\pi (6x)^2 = 36 \pi x^2$

Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard = $266x^2$ - $36 \pi x^2$
=> Final area of the Yard = $2x^2(133 - 18 \pi)$ (Option D)

6. Ans: Option (A) $56x^2$

Explanation:
First let's find the total area of the lot:
Total Area of the lot= 6x * 10x = $60x^2$

Now the area of the stadium:
Area of the stadium = 1x * 4x = $4x^2$

Now the final Area of the lot would be:
Final area of the lot= Total Area of the lot - Area of the stadium
Final area of the lot= $60x^2$ - $4x^2$
=> Final area of the lot = $56x^2$ (Option A)

-i

4 0

3 years ago

Read 2 more answers