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Amanda [17]
3 years ago
11

Help me please with this

Mathematics
1 answer:
makkiz [27]3 years ago
6 0

Answer:

r = 42

Step-by-step explanation:

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1. The factors of a2 - 9 are
Mazyrski [523]

Answer:

Step-by-step explanation:

1. (a+3)(a-3) = a²+3a-3a-9 = a²-9

2. a linear equation consists of a polynomial of degree one.

5 0
3 years ago
What two numbers multiply to -126 and add up to -65
Airida [17]
Xy = -126
x + y = -65

xy = -126
\frac{xy}{x} = \frac{-126}{x}
y = \frac{-126}{x}

x + y = -65
x + \frac{-126}{x} = -65
\frac{x^{2}}{x} + \frac{-126}{x} = -65
\frac{x^{2} - 126}{x} = -65
-65x = x^{2} - 126
0 = x^{2} + 65x - 126
x = \frac{-(65) \+ \sqrt{(65)^{2} - 4(1)(-126)}}{2(1)}
x = \frac{-65 \± \sqrt{4225 + 504}}{2}
x = \frac{-65 \± \sqrt{4729}}{2}
x = \frac{-65 \± 68.8}{2}
x = \frac{-65 + 68.8}{2}  or  x = \frac{-65 - 68.8}{2}
x = \frac{3.8}{2}  or  x = \frac{-133.8}{2}
x = 1.9  or  x = -66.9

     x + y = -65
  1.9 + y = -65
- 1.9           - 1.9
           y = -66.9
    (x, y) = (1.9, -66.9)

or

        x + y = -65
  -66.9 + y = -65
+ 66.9        + 66.9
              y = 1.9
        (x, y) = (-66.9, 1.9)

The two numbers that add up to -65 and can multiply to -126 are the numbers -66.9 and 1.9.
3 0
3 years ago
A watermelon was ejected from a catapult reaching a maximum height of 20 ft. The watermelon left the catapult when it was 4 ft o
Paraphin [41]

Answer:

Step-by-step explanation:

No, the equation cannot be written with the given information. The distance from the catapult when the watermelon reached the maximum height is needed. Since the watermelon did not start on the ground, it cannot be assumed that the maximum was reached half the distance to the landing point.

5 0
3 years ago
Pls help I don't understand:
sineoko [7]

Answer:

Part a) T(d)=2d+30

Part b) T(6)=42\ minutes

Step-by-step explanation:

Part a) Write an equation for T (d)

Let

d ----> the number of days

T ---> the time in minutes of the treadmill

we know that

The linear equation in slope intercept form is equal to

T=md+b

where

m is the slope or unit rate

b is the y-intercept or initial value

In this problem we have

The slope or unit  rate is

m=2\ \frac{minutes}{day}

The y-intercept or initial value is

b=30\ minutes

substitute

T(d)=2d+30

Part b) Find T (6), the minutes he will spend on the treadmill on day 6

For d=6

substitute in the equation and solve for T

T(6)=2(6)+30

T(6)=42\ minutes

8 0
3 years ago
Identify the x-intercept and y-intercept of the equation below.
Lady_Fox [76]
Divide by 21 to put the equation in intercept form.
  x/(21/9) + y/(-21/7) = 1
  x/(7/3) + y/(-3) = 1

The x-intercept is (7/3, 0)
The y-intercept is (0, -3)

The 3rd choice is appropriate.

8 0
3 years ago
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