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34kurt
3 years ago
10

Use the protractor to measure each angle formed by the intersecting lines.

Mathematics
1 answer:
kolezko [41]3 years ago
7 0

Answer:

ABC=140°

CBD=70°

DBE=140°

ABE=140°

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Segment YZ has endpoints (6, 3) and (3, 9). Find the coordinates of the point that divides the line segment directed from Y to Z
fenix001 [56]

Answer:

  (4, 7)

Step-by-step explanation:

The point of interest is ...

  P = (2Z +1Y)/(2+1) = ((2·3+6)/3, (2·9+3)/3)

  P = (4, 7)

__

The point that divides the segment into the ratio a:b is the weighted average of the endpoints, with the weights being "b" and "a". The weight of the first end point corresponds to the length of the far end of the segment.

8 0
3 years ago
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Use the distributive property to multiply. Simplify your Answer.<img src="https://tex.z-dn.net/?f=%283y%20%2B%205%29%283y%5E%7B2
trapecia [35]
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3 years ago
What statement is true?
givi [52]

Answer:

\frac{18}{32}>\frac{16}{32}

Step-by-step explanation:

We need to find which statements are true.

Solution to find the same we will solve each statement and will conclude the same.

1.  \frac{14}{21}>\frac{17}{24}

Now On solving we get;

\frac{14}{21} = 0.66

\frac{17}{24}=0.70

So we can see that 0.70 > 0.66

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2. \frac{18}{32}>\frac{16}{32}

Now On solving we get;

\frac{18}{32}=0.5625

\frac{16}{32}= 0.5

So we can see that 0.5625 > 0.5

Hence The given statement is True.

3.  \frac{20}{15}

Now On solving we get;

\frac{20}{15} = 1.33

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So we can see that 1.33 > 1.2

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4.  \frac{29}{35}

Now On solving we get;

\frac{29}{35}= 0.82

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7 0
3 years ago
What is 1+12x-40 evaluated
vlada-n [284]

Answer:

12x-39

Step-by-step explanation:

40-1=39

7 0
3 years ago
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HELP! WILL GIVE BRANLIEST!
mars1129 [50]

Answer:

D

Step-by-step explanation:

This is your answer because first you have 3x10-6 and 2x1030 what you have to do is that first you multiply 3 x 2 equals to 6 then, 10 x 1 = 10 then you have to multiply 30 x 6 = 180 then you put it together and your answer is 6x10-180

Hope this helps :)

pls mark me brainlist

8 0
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