<u>Given</u>:
The system of linear equations are
and 
We need to determine the solution to the system of equations using substitution method.
<u>Solution</u>:
The solution can be determined using the substitution method.
Let us substitute
in the equation 
Thus, we have;




Thus, the value of y is -17.
Substituting
in the equation
, we get;


Thus, the value of x is -13.
Hence, the solution to the system of equations is (-13,-17)
B. This is the answer because it is not equivalent to anything else, and the answer simplified is: -18.
4.185 divided by 0.93 is 4.5

a=1, b=-4, c=3
If the vertex has coordinates (2;-1)(p=2,q=-1) we can write vertex form of a parabola equation:


We need to put (x-2) at the place of (x) in f(x) equation to get g(x)
![g(x)=1[(x-2)-2]^2-1](https://tex.z-dn.net/?f=g%28x%29%3D1%5B%28x-2%29-2%5D%5E2-1)


So:
p=4, q=-1
Vertex of the parabola defined by g(x)=f(x-2) has the vertex at
:)