Please help<br> _____________<br> ______<br> ___________<br> _____

The model represents an equation. What value of x makes the equation true?

Cerrena [4.2K]

Answer:

C

Step-by-step explanation:

(-3) x 4 = (-12) + 6 = -6

3 + 3 = 6 + (-12) = -6

(-6) = (-6)

Because adding positive to negative is like subtracting the negative if that makes sense.

Hope this helps!

Have a great day!

Plz mark brainliest

6 0

3 years ago

Read 2 more answers

Please help me this is due today

Evgen [1.6K]

Split the room into 2 rectangles
area = 5*4 + 3*3 = 29 sq ft

So the cost is 29*8 = $232

6 0

3 years ago

What percentage of tommy's coins are dimes?

Naya [18.7K]

The percentage would be about 64%

5 0

3 years ago

In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.

jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

$\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}$

$\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}$

$\text{The weight of average pumpkin}=5\text{ kg}$

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

$1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}$

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

3 0

3 years ago

Read 2 more answers

Help me please!!!! i dont now the answer

Marat540 [252]

-1/10 is your answer .

7 0

3 years ago

Please help _____________ ______ ___________ ______

Please help _______ _