Answer:
Step-by-step explanation:
Th correct one is the third box
plz mark me brainliest
Hello,
I am going to remember:
y'+3y=0==>y=C*e^(-3t)
y'=C'*e^(-3t)-3C*e^(-3t)
y'+3y=C'*e^(-3t)-3Ce^(-3t)+3C*e^(-3t)=C'*e^(-3t) = t+e^(-2t)
==>C'=(t+e^(-2t))/e^(-3t)=t*e^(3t)+e^t
==>C=e^t+t*e^(3t) /3-e^(3t)/9
==>y= (e^t+t*e^(3t)/3-e^(3t)/9)*e^(-3t)+D
==>y=e^(-2t)+t/3-1/9+D
==>y=e^(-2t)+t/3+k
Answer:
I would say too broad.
Step-by-step explanation:
The answer I got was 417/50 hope this helps you
Here's how it works:
12+12+x+6+x+6=64
36+2x=64 <Combine like terms
2x=28 <Subtract 36
x=14 <Divide by two