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drek231 [11]
2 years ago
11

Describe how to transform the graph of g(x)=ln(x) in the graph of f(x) = ln(-x)-9

Mathematics
1 answer:
valentina_108 [34]2 years ago
3 0

Answer:

the answer is d because it's reflects

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The equation would be 3(x + 5)
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PLEASEEEE HELPP!!! 6-2+9a-4a+a+7 <br> PLEASEE HELP THIS IS URGENT!!!! pelaseeeeee helppp
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3 years ago
Fill in the missing numbers to complete the linear equation that gives the rule for this table.
irakobra [83]

The value of the missing number to complete the linear equation are 31 and -10 respectively.

What is Algebraic expression ?

Algebraic expressions are the idea of expressing numbers using letters or alphabets without specifying their actual values. The basics of algebra taught us how to express an unknown value using letters such as x, y, z, etc. These letters are called here as variables. An algebraic expression can be a combination of both variables and constants. Any value that is placed before and multiplied by a variable is a coefficient.

Here the given tables shows the coordinates of the linear equation and to find the equation  we consider any two points let suppose the those two points be (0,-10) and (1,21).

Now using slope formula to find the slope of line m :

m = (y₂-y₁)/ (x₂-x₁)

m = (21-(-10))/(1-0)

m = 31

Let us first find the equation of the line using point-slope equation of line :

(y-y₁) = m(x-x₁)

Substituting all the values in above equation to get the equation of line :

(y-(-10)) = 31(x-0)

(y+10) = 31x

y = 31x - 10

Therefore, the value of the missing number to complete the linear equation are 31 and -10 respectively.

check and know more about slope of line here :

brainly.com/question/14914699

#SPJ1

8 0
1 year ago
What are the roots of this quadratic equation?
pickupchik [31]

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2

Step-by-step explanation:

im the best in the world

5 0
2 years ago
Find the angle between u = (8.- 3) and v = (-3,- 8) Round to the nearest tenth of a degree.
Nimfa-mama [501]

Answer:

<h2>90°</h2>

Step-by-step explanation:

First you must calculate the module or the magnitude of both vectors

The module of u is:

|u|=\sqrt{(8)^2 + (-3)^2} \\\\|u|=\sqrt{64 + 9}\\\\|u|=8.544

The module of v is:

|v|=\sqrt{(-3)^2 + (-8)^2} \\\\|u|=\sqrt{9 + 64}\\\\|u|=8.544

Now we calculate the scalar product between both vectors

u*v = 8*(-3) + (-3)*(-8)\\\\u*v = -24+ 24=0

Finally we know that the scalar product of two vectors is equal to:

u*v = |u||v|*cos(\theta)

Where \theta is the angle between the vectors u and v. Now we solve the equation for \theta

0 = 8.544*8.544*cos(\theta)\\\\0 = cos(\theta)\\\\\theta= arcos(0)\\\\\theta=90\°

the answer is 90°

Whenever the scalar product of two vectors is equals to zero it means that the angle between them is 90 °

5 0
3 years ago
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