I guess you want to know the total amount after one year. If so, the interest yielded after one year is 350 x 4% = $14 and her new capital becomes
350 (initial capital) + 14 (interest over 1 year) = 350+14 = $364
Hello here is a solution
look graph :
the curve : color blue
the first tangent : y = 0.13x +1.87 color Pink
the second tangent : y = 1.88 x +0.14 color green
The hypothesis test shows that we reject the null hypothesis and there is sufficient evidence to support the claim that the return rate is less than 20%
<h3>What is the claim that the return rate is less than 20% by using a statistical hypothesis method?</h3>
The claim that the return rate is less than 20% is p < 0.2. From the given information, we can compute our null hypothesis and alternative hypothesis as:


Given that:
Sample size (n) = 6965
Sample proportion 
The test statistics for this data can be computed as:



z = -2.73
From the hypothesis testing, since the p < alternative hypothesis, then our test is a left-tailed test(one-tailed.
Hence, the p-value for the test statistics can be computed as:
P-value = P(Z ≤ z)
P-value = P(Z ≤ - 2.73)
By using the Excel function =NORMDIST (-2.73)
P-value = 0.00317
P-value ≅ 0.003
Therefore, we can conclude that since P-value is less than the significance level at ∝ = 0.01, we reject the null hypothesis and there is sufficient evidence to support the claim that the return rate is less than 20%
Learn more about hypothesis testing here:
brainly.com/question/15980493
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<h3>
Answer: Yes, it is a function</h3>
This is a function because there are no x values that repeat.
If we had repeated x values, then this would mean a certain input x leads to multiple outputs y, and that would not make it a function.
For instance, if we had (2,1) and (2,2) at the same time, then the input x = 2 leads to multiple outputs y = 1 and y = 2 at the same time. A function would not be possible in this example.
A function is only possible if any input x leads to exactly one output y. It is possible for y to repeat itself and still have a function.