<u>Answer:</u> The initial molarity of cation is 2.38 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Given mass of = 46.3 g
Molar mass of = 129.6 g/mol
Volume of solution = 150 mL
Putting values in above equation, we get:
1 mole of produces 1 mole of cation and 1 mole of anion
So, molarity of cation = (1 × 2.38) = 2.38 M
Hence, the initial molarity of cation is 2.38 M
False. A buffering solution consists of a WEAK acid such as CH3COOH, C5H5N, or ammonia. <span>A buffering solution resists pH change upon the addition of an acidic or basic components. It can neutralize little amounts of added acid or base, thus maintaining the pH of the solution relatively stable. The correct answer is letter "B. false"</span>
Molarity= moles of solute / liters of solution
2moles/0.75 L= ???? M
Answer:
Chlorine tetrachloromethane
Explanation: