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3 years ago

6

Erika had three pieces of ribbon . Each piece is 25 yards long. She needs to cut pieces that are 22 inches long . What is the gr

eatest number of 22-inch pieces that she can cut from the three pieces of ribbon?
A) 123
B)120
C)41
D)40

1 answer:

Kisachek [45]3 years ago

4 0

B. 120 because you cant glue the ribbon together, simply multiply 25 by 3 multiply that by 12 divide that by 22 then multiply that by 3

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Consider the sequence defined recursively by do = 0, an = an-1 + 3n – 1. a) Write out the first 5 terms of this sequence,

creativ13 [48]

Answer:

The first 5 terms of the sequence is 2,7,15,26,40.

Step-by-step explanation:

Given : Consider the sequence defined recursively by $a_0=0$ $a_n=a_{n-1}+3n-1$

To find : Write out the first 5 terms of this sequence ?

Solution :

$a_n=a_{n-1}+3n-1$ and $a_0=0$

The first five terms in the sequence is at n=1,2,3,4,5

For n=1,

$a_1=a_{1-1}+3(1)-1$

$a_1=a_{0}+3-1$

$a_1=0+2$

$a_1=2$

For n=2,

$a_2=a_{2-1}+3(2)-1$

$a_2=a_{1}+6-1$

$a_2=2+5$

$a_2=7$

For n=3,

$a_3=a_{3-1}+3(3)-1$

$a_3=a_{2}+9-1$

$a_3=7+8$

$a_3=15$

For n=4,

$a_4=a_{4-1}+3(4)-1$

$a_4=a_{3}+12-1$

$a_4=15+11$

$a_4=26$

For n=5,

$a_5=a_{5-1}+3(5)-1$

$a_5=a_{4}+15-1$

$a_5=26+14$

$a_5=40$

The first 5 terms of the sequence is 2,7,15,26,40.

5 0

3 years ago

A university administrator was interested in determining if there was a difference in the distance students travel to get from c

eduard

Answer:

1) Fail to reject the Null hypothesis

2) We do not have sufficient evidence to support the claim that the mean distance students traveled to school from their current residence was different for males and females.

Step-by-step explanation:

A university administrator wants to test if there is a difference between the distance men and women travel to class from their current residence. So, the hypothesis would be:

$H_{o}: \mu_{F}-\mu_{M}=0\\\\ H_{a}: \mu_{F}-\mu_{M}\neq 0$

The results of his tests are:

t-value = -1.05

p-value = 0.305

Degrees of freedom = df = 21

Based on this data we need to draw a conclusion about test. The significance level is not given, but the normally used levels of significance are 0.001, 0.005, 0.01 and 0.05

The rule of the thumb is:

If p-value is equal to or less than the significance level, then we reject the null hypothesis
If p-value is greater than the significance level, we fail to reject the null hypothesis.

No matter which significance level is used from the above mentioned significance levels, p-value will always be larger than it. Therefore, we fail to reject the null hypothesis.

Conclusion:

We do not have sufficient evidence to support the claim that the mean distance students traveled to school from their current residence was different for males and females.

7 0

4 years ago

The average sunflower has 34 petals. What is the best estimate of the total number of petals on 57 sunflowers?

stellarik [79]

Your initial instinct would be to solve this problem with this solution. 34 x 57 = 1,938 petals.

However, the word estimate is present; therefore, we have to consider that we need to get the approximate number and not the exact number of petals.

There is a general rule regarding estimation or approximation. You have to round it to the nearest place you have based on. In this problem we round it off to the nearest tens place.

If the number is below 5, you round it down: 34 is rounded down to 30 petals.

If the number is above 5, you round it up: 57 is rounded up to 60 sunflowers.

Thus, your equation would be : 30 x 60 = 1,800 petals (best estimate)

3 0

3 years ago

Write the equition of the line that passes through the pair of points (8,-8) and (9,-4)

ANTONII [103]

Answer: More Info

Step-by-step explanation:

8 0

4 years ago

Can someone help me with number 10, 11, 12, 15, and 16 I don’t understand them thanks

yanalaym [24]

10)

$10^2-48:6+25*3=100-8+75=167$

11)

$8(\frac{16}{4} )+2^2-11*3=32+4-33=3$

12)

$(\frac{6}{3} +4)^2:4*7=(2+4)^2:4*7=6^2:4*7=36:4*7=9*7=63$

13) (your answer is incorrect)

$5(9-4)^2-3^2=5*5^2-3^2=5*25-9=125-9=116$

14) (your answer is incorrect)

$5^2-2^2*4^2-12=25-4*16-12=25-64-12=-51$

15)

$(\frac{50}{5^2} )^2:4=(\frac{50}{25} )^2:4=2^2:4=4:4=1$

16)

$\frac{24+32+30+28}{2}$ -expression to represent this situation

$\frac{24+32+30+28}{2}=\frac{114}{2}=57$

Answer: In 1 group 57 students

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P.S. Hello from Russia :^)

4 0

3 years ago