Please help this is due tomorrow and I don't understand it, The Zeros of a
1 answer:
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Answer:
volume of fodder=1/3pie R^2h=
l^2=r^2+h^2
l^2=(2.1)^2+(3.6)^2
l^2=4.441+12.96=17.37
l==4.17m
minimum area of polythene to cover fodder=pieRl=
the volume of fodder is and minimum area of polythene to cover fodder in the rainy seasonv47.18m^3