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ehidna [41]
4 years ago
12

Find the value of +c15 when =c4.

Mathematics
1 answer:
Montano1993 [528]4 years ago
6 0
It equals 60 u do 15* 4
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Answer part 1 and part 2 please I need help
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Step-by-step explanation:

<u>Step 1:  Answer the first question</u>

Area of a triangle → A = \frac{b*h}{2}

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Total Area → 12 * 2=24

Answer:  Option D, 24\ square\ units

<u>Step 2:  Answer the second question</u>

We know that the total side length is 12 but we also know that the triangle base is 4 so we would subtract that from the total length and we get that the rectangle length is 8.  We also know that the width is 6 so we multiply 8 by 6 and we add 24.  This matches option B

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5. Which one of the following is an example of a repeating decimal?
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Q and R are not mutually exclusive events. If P(Q)=5/8 and P(R)=1/8 and P(Q and R)=1/32,Find P(q or R)
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The solution for this problem is just adding and subtracting fractions. We all know how to add and subtract function because our teacher since high school teach us how to. P(Q or R) = P(Q) + P(R) - P(Q and R) = 5/8 + 1/8 - 1/32 = 23/32

The answer to this question is 23/32.
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Let f(x) = 1850(0.96)^x<br><br> b) Solve the equation f(x+1) = f(x) -25
Anton [14]

Answer:

(a) -69.59 . . . . the approximate slope of the curve at x=2

(b) 26.583 . . . . the value of x where the slope of f(x) is about -25.

Step-by-step explanation:

(a) The slope of a function <em>f </em>over the interval [x, x+h] is given by ...

... slope = (f(x+h) -f(x))/h

The problem statement asks for the value of ...

... (f(2.01) -f(2))/0.01

Matching this expression to the pattern above, we find x = 2, h = 0.01. An appropriate interpretation of the expression is that it gives the approximate slope of f(x) near x=2.

The value of that slope is about ...

... (f(2.01) -f(2))/0.01 ≈ 1850·(0.92122386 -0.9216)/.01 ≈ -69.5857

(b) f(x+1) = 1850·0.96^(x+1) = 0.96·f(x)

Then the equation becomes ...

... 0.96·f(x) = f(x) -25

... 25 = 0.04·f(x) . . . . . . . . add 25-0.96·f(x)

... 625 = f(x) . . . . . . . . . . . multiply by 25

... 625 = 1850·0.96^x . . . substitute definition of f(x)

... 625/1850 = 0.96^x . . . divide by the coefficient of the exponential term

... log(625/1850) = x·log(0.96) . . . . take logs

... x = log(625/1850)/log(0.96) ≈ -0.471292/-0.0177288

... x ≈ 26.583

If you rearrange the equation to ...

... f(x+1) -f(x) = -25

Comparing this to the equation for slope, above, it looks a lot like we're trying to find the interval [x, x+1] over which the average slope is -25.

6 0
4 years ago
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