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2 years ago

6

2. What is the area of the half circle ?

1 answer:

Drupady [299]2 years ago

5 0

The answer is 127.17

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(Hypothetical.) Suppose a certain person's reaction time, in seconds, for pressing a button on a visual cue has the following cu

Sonbull [250]

Answer:

the probability the person's reaction time will be between 0.9 and 1.1 seconds is 0.0378

Step-by-step explanation:

Given the data in the question;

the cumulative distribution function F(x) = $1 - \frac{1}{(x + 1)^3}$ ; $x > \theta$

probability the person's reaction time will be between 0.9 and 1.1 seconds

P( 0.9 < x < 1.1 ) = P( x ≤ 1.1 ) - P( x ≤ 0.9 )

P( 0.9 < x < 1.1 ) = F(1.1) - F(0.9)

= [ $1 - \frac{1}{(x + 1)^3}$ ] - [ $1 - \frac{1}{(x + 1)^3}$ ]

we substitute

= [ $1 - \frac{1}{(1.1 + 1)^3}$ ] - [ $1 - \frac{1}{(0.9 + 1)^3}$ ]

= [ $1 - \frac{1}{(2.1)^3}$ ] - [ $1 - \frac{1}{(1.9)^3}$ ]

= [ $1 - \frac{1}{(9.261)}$ ] - [ $1 - \frac{1}{(6.859)}$ ]

= [ 1 - 0.1079796998 ] - [ 1 - 0.1457938 ]

= 0.8920203 - 0.8542062

= 0.0378

Therefore, the probability the person's reaction time will be between 0.9 and 1.1 seconds is 0.0378

5 0

3 years ago

7.5% of $12.58<br> ANSWER PLS

podryga [215]

Answer:

0.94$

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

a piece of property is bought at $105,000 and its value decines at a continous rate of 1.5%. how much is the property worth afte

likoan [24]

U have to add then duivide ok

8 0

3 years ago

A group of 10 friends are in line to see a movie. The table shows how much different groups will pay in all. Predict how much t

slega [8]

Answer: Wheres the table

Step-by-step explanation:

4 0

3 years ago

Fred walked a trail at 2 mph. Paul started 30 minutes later on the same trail and walked at a pace of 3 mph. Create a system of

spayn [35]

Answer:

$y=2x\\y=3(x-\frac{1}{2})$

Paul will catch Fred after $1\ hours$ at a distance $3\ miles$ .

Step-by-step explanation:

Distance is represented by $y$ and the time is represented by $x$ . Here after $x$ hours(when Fred started) the distance covered by Fred and Paul is same that is $y$ .

For Fred:

time= $x$

distance= $y$

Speed $=2\ mph$

$Distance=speed\times time\\y=2\times x \\y=2x$

Paul:

Since Fred started 30 minutes earlier, so Paul's travel time will be 30 minutes less than that of Fred.

Time $=x-\frac{1}{2}$

Speed $=3\ mph$

Distance $=y\\$

$y=3\times (x-\frac{1}{2})\\y=3(x-\frac{1}{2})$

Hence system of equation

$y=2x\\y=3(x-\frac{1}{2})$

Solution of this system of equations gives the time, when Paul will catch Fred and distance covered by each of them.

$y=2x\\y=3(x-\frac{1}{2})\\\\2x=3x-\frac{3}{2}\\x=\frac{3}{2}\\\\y=2x\\y=2\times \frac{3}{2}\\y=3$

Time taken by Paul $=x-\frac{1}{2}=\frac{3}{2}-\frac{1}{2}=1$

Hence Paul will catch Fred after $1\ hours$ at a distance $3\ miles$ .

3 0

3 years ago