Answer:
The first five terms are;
-3,-7,11,-29,69
Step-by-step explanation:
The recursive definition of the sequence is
,
and
.
When n=3, we obtain;
.
.
.
.
When n=4
.
.
When n=5
.
.
Therefore the first five terms are;
-3,-7,11,-29,69
1\3h-2.7+12=2\3h-6
-2.7+12+6=2\3h-1\3h
15.3=1\3h multiply both sides by 3
45.9=h
Answer:
no. 1 a=37,no.2 b=12 thanks for your question which help to improve my knowledge
Answer:
x = √2/2
Step-by-step explanation:
Use the identity:
arcsin x + arccos x = π/2
Therefore, we can rewrite this as:
arcsin x (π/2 − arcsin x) = π²/16
If we substitute y = arcsin x:
y (π/2 − y) = π²/16
π/2 y − y² = π²/16
0 = y² − π/2 y + π²/16
0 = 16y² − 8π y + π²
0 = (4y − π)²
y = π/4
Substituting back:
arcsin x = π/4
x = sin(π/4)
x = √2/2