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FromTheMoon [43]
2 years ago
13

The sum of the number is 103.the second number is 4 times the third.the third number is 5 more then the first .what are the numb

ers ?
Mathematics
1 answer:
Zigmanuir [339]2 years ago
4 0

Answer:

13, 18, 72

Step-by-step explanation:

let x-5 represent the first number, since the first number is 5 less than the third number. let x represent the third number. let 4x represent the third number, since it's four times greater than the third number.

set up an equation, and make it equal to 103:

x-5+x+4x=103

solve:

6x-5=103

6x=108

x=18

so, the third number is 18.

the first number is equal to x-5, so:

18-5=13

the second number is equal to 4x, so:

4(18)=72

so, the three numbers are 13, 18, and 72.

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Find the first five terms of the sequence given the following recursive formula:
forsale [732]

Answer:

The first five terms are;

-3,-7,11,-29,69

Step-by-step explanation:

The recursive definition of the sequence is

a_1=-3,, a_2=-7 and a_n=a_{n-2}-2a_{n-1}.

When n=3, we obtain;

a_3=a_{3-2}-2a_{3-1}.

\implies a_3=a_{1}-2a_{2}.

\implies a_3=-3-2(-7).

\implies a_3=11.

When n=4

\implies a_4=a_{2}-2a_{3}.

\implies a_4=-7-2(11)=-29.

When n=5

\implies a_5=a_{3}-2a_{4}.

\implies a_4=11-2(-29)=69.

Therefore the first five terms are;

-3,-7,11,-29,69

5 0
3 years ago
Trigonometry that’s due in one hour :(
expeople1 [14]

Answer:

(a)  \theta=\tan^{-1}(-0.890)

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\implies \theta=138\textdegree, 318\textdegree

(b)  \theta=\cos^{-1}\left(\dfrac{\sqrt{3} }{2}\right)

\implies \theta=30 \textdegree \pm360 \textdegree n, 330 \textdegree \pm360 \textdegree n

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(c)  \theta=\sin^{-1}\left(\dfrac{1 }{2}\right)

\implies \theta=30 \textdegree \pm360 \textdegree n, 150 \textdegree \pm360 \textdegree n

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3 0
2 years ago
How do i solve 1/3h-4(2/3h-3) = 2/3h-6??
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kobusy [5.1K]

Answer:

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2 years ago
Solve the equation:
ivann1987 [24]

Answer:

x = √2/2

Step-by-step explanation:

Use the identity:

arcsin x + arccos x = π/2

Therefore, we can rewrite this as:

arcsin x (π/2 − arcsin x) = π²/16

If we substitute y = arcsin x:

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