Im finding it...
Step-by-step explanation:
Answer:
Option B. f¯¹(x) = ³√(– x – 9)
Step-by-step explanation:
From the question given above:
f(x) = – x³ – 9
f¯¹(x) =?
We can obtain the inverse f¯¹(x) of the above equation by doing the following:
f(x) = – x³ – 9
Replace f(x) with y
y = – x³ – 9
Interchange x and y
x = – y³ – 9
Make y the subject . This is illustrated below:
x = – y³ – 9
Rearrange
x + 9 = – y³
Multiply through by –1
–(x + 9) = y³
y³ = – x – 9
Take the cube root of both side
y = ³√(– x – 9)
Replace y with f¯¹(x)
f¯¹(x) = ³√(– x – 9)
Thus, the inverse of the function
f(x) = – x³ – 9
is
f¯¹(x) = ³√(– x – 9)
Answer:
the other zeros of this function are {-2, 3}
Step-by-step explanation:
Use synthetic division to find the roots. The coefficients of this cubic function are 1, -2, -5, 6, and we begin by using 1 as our first divisor:
1 / 1 -2 -5 6
+1 -1 -6
--------------------------
1 -1 -6 0
Because the remainder is zero (0), we can conclude that 1 is indeed a root of the given polynomial. The quotient is 1x^2 - 1x - 6, whose roots can be found either through synthetic division or factoring. In this case the factors are (x - 3) and (x + 2), so the other zeros of this function are {-2, 3}.
