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3 years ago

7

Please help me out! :)

1 answer:

quester [9]3 years ago

3 0

Answer:

a) A(8,-3), B(4,-3), C(2,5)

b) not sure sry

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A 6.3<br> B 7.5<br> C 6.7<br> D 6.5

Arlecino [84]

So in this case use sine to figure this out.

To convert 48 to the ratio, you gotta use a calculator unless you've memorized everything. do sin(48), which equals about 0.74.

Since Sin is opposite / hypotenuse, 5/h must equal 0.74

So do 5 / 0.74 to get about 6.76 as your answer.

3 0

3 years ago

Can someone help me do this expression 6+(8÷2)-2+(4-1)

trasher [3.6K]

<h3><u>QUES</u><u>TION</u><u>:</u></h3>

can someone help me do this expression 6+(8÷2)-2+(4-1)

<h3><u>SOLU</u><u>TION</u><u> AND</u><u> ANSWER</u><u>:</u></h3>

CALCULATING THE VALUE

Divide first 8 and 2 and subtract 4 - 1

$\large \sf = 6 + 4 - 2 + (4 - 1)$

$\large \sf = 6 + 4 - 2 + 3$

Lastly calculate the sum or difference

$\sf \: calculate \: the \: sum \: of \: the \: positive \: numbers \: \: \large \sf \rightarrow \red{6 + 4} - 2 \red{+ 3}$

$\large \sf = 13 - 2$

$\large \sf = 11$

<h3><u>FINAL</u><u> </u><u>ANSWER</u><u>:</u></h3>

$\huge \orange{ \underline{ \boxed{11}}}$

HOPE THIS HELP YOU! HAVE A NICE DAY!

~kimtaetae92~

3 0

3 years ago

77julia77 [94]

Answer:

B, C, F

Step-by-step explanation:

Given:

$\left\{\begin{array}{l}4x+3y=12\\ \\2x+3y=-6\end{array}\right.$

Subtract the second equation from the first equation:

$(4x+3y)-(2x+3y)=12-(-6)\\ \\4x+3y-2x-3y=12+6\\ \\2x=18\\ \\x=9$

Option B "The x coordinate of the solution is 9" is ture

Substitute it into the first equation:

$4\cdot 9+3y=12\\ \\36+3y=12\\ \\3y=12-36\\ \\3y=-24\\ \\y=-8$

Option F "The y coordinate of the solution is -8" is true.

Point (9,-8) is in the IV quadrant, so option C is true.

8 0

3 years ago

Find the value of the expression 0.5^10/0.5^7

SIZIF [17.4K]

Answer:

The solution is:

$\frac{0.5^{10}}{0.5^7}=0.125$

Step-by-step explanation:

Given the expression

$0.5^{10}\div 0.5^7$

Solving

$\frac{0.5^{10}}{0.5^7}$

$\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}$

so

$\frac{0.5^{10}}{0.5^7}=0.5^{10-7}$

$\mathrm{Subtract\:the\:numbers:}\:10-7=3$

$=0.5^3$

$=0.125$ ∵ $0.5^3=0.125$

Therefore, the solution is:

$\frac{0.5^{10}}{0.5^7}=0.125$

7 0

3 years ago

Neko [114]

Answer:

a.

$t\leqslant 400$

3 0

3 years ago

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