Your answer would be 15. You first would move the "pretend" decimal to the left 2 times. so it would end up being 0.25. So then you would set up your problem. 0.25 x 60 =. Which should give you the answer of 15.
Answer:
We conclude that the set of numbers x satisfying -7 ≤ x ≤ 4 is an interval that contains -7, 4, and all numbers in between.
Thus, the domain of g is: -7 ≤ x ≤ 4
Step-by-step explanation:
We know that the domain of a function is the set of inputs or argument values for which the function is defined.
From the given graph, it is cleared that the function g starts from the x-value x = -7 and ends at x = 4.
It means the function is defined for the set of input values from x = -7 to x = 5 for which the function is defined.
Therefore, we conclude that the set of numbers x satisfying -7 ≤ x ≤ 4 is an interval that contains -7, 4, and all numbers in between.
Thus, the domain of g is: -7 ≤ x ≤ 4
Answer:
−y−1=3
Step-by-step explanation:
Which equation can be used to find the solution of (1/4)^y+1=64?
This can be solved by power of indices
(1/4)^(y+1)=64
(4^-1)^(y + 1)= 4^3
Note
(x^a)^b = x^ab
Hence:
4^(-1)(y + 1)= 4^3
4^-y - 1 = 4^3
Divide both sides by 4
−y−1=3
Hence, the equation that can be used to find the solution of (1/4)^y+1=64 is
−y−1=3
Answer: parallel lines have the same slope as the original so the slope would still be -x
Step-by-step explanation:
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Step-by-step explanation:
