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Alex Ar [27]
4 years ago
6

A segment measures 10 units. One end of the segment has an endpoint at three, -6. What is another possible in point to this segm

ent
Mathematics
2 answers:
frosja888 [35]4 years ago
4 0
Assumingn ya mean the oint (3,-6)

add or subtract 10 from x or y to get points 10 away

3-10=-7 so a point is (-7,-6)
3+10=13 so a point is (13,-6)
-6-10=-16 so a point is (3,-16)
-6+10=4 so a point is (3,4)

those are 4 out of inifnite points that we can get that are 10 units from (3,-6)
the points are (x,y) such that they satisfy the following equation:
(x-3)^2+(y+6)^2=10^2
prohojiy [21]4 years ago
3 0
If one end is -6 and the measure is 10 units long, there are 2 other possible ends. -16 or 6.
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Given a coordinate point (x, y), the first value of the point represents the value on the x-axis while the second value represent the value on the y-axis.

1.) To express the values (-4, -1), (-1, 2), (1, -4), (2, -3), (4, 3) as a table, we have:

 x          y
-4         -1
-1          2
 1         -4
 2         -3
 4          3

The values (-4, -1), (-1, 2), (1, -4), (2, -3), (4, 3) expressed as a graph have been attached as graph_1


To express the values (-4, -1), (-1, 2), (1, -4), (2, -3), (4, 3) as a mapping, we have two circles with one labelled x and the other one labelled y.
Inside the circle labelled x are the numbers -4, -1, 1, 2, 4 written vertically and inside the circle labelled y are the numbers -4, -3, -1, 2, 3 written vertically.
There are lines joining from the circle labelled x to the circle labelled y with line joining -4 in circle x to -1 in circle y, -1 in circle x to 2 in circle y, 1 in circle x to -4 in circle y, 2 in circle x to -3 in circle y, 4 in circle x to  3 in circle y.

The domain of the relation is the set of the x-values of the relation, i.e. domain is {-4, -1, 1, 2, 4}.
The range of the relation is the set of the y-values of the relation, i.e. range is {-4, -3, -1, 2, 3}

2.) To express the values (-2, 1), (-1, 0), (1, 2), (2, -4), (4, 3) as a table, we have:

 x          y
-2         1
-1         0
 1          2
 2         -4
 4          3

The values (-2, 1), (-1, 0), (1, 2), (2, -4), (4, 3) expressed as a graph have been attached as graph_2


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There are lines joining from the circle labelled x to the circle labelled y with a line joining -2 in circle x to 1 in circle y, -1 in circle x to 0 in circle y, 1 in circle x to 2 in circle y, 2 in circle x to -4 in circle y, 4 in circle x to  3 in circle y.

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The range of the relation is the set of the y-values of the relation, i.e. range is {-4, 0, 1, 2, 3}
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