Ions and charges= Al+3 SO3-2
The charges must add up to zero, in order for two +3 aluminum ions to cancel out three -2 sulfite ions.
Al+3 Al+3 SO3-2 SO3-2 SO3-2
<span>So simply put : </span>Al2(SO3)<span>3 </span>
Answer: 2 Acetate ions
Explanation:
Strontium Acetate, has the molecular formular to be; C4H6O4Sr ( or in a linear form, Sr(CH3COO)2), contains two acetate ions.
Answer:
The key difference between rhombic and monoclinic sulphur is that the rhombic sulphur is the most stable allotropic form of sulphur that exists as rhombic octahedral crystals whereas the monoclinic sulphur exists as long, needle-shape prisms but, it is stable only at temperatures between 96◦C and 119◦C.
Explanation:
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Answer:
Explanation:
Use the position of an element in the periodic table to deduce its valence.
The periodic table is a table that groups elements based on their periodic functions. A group is a vertical arrangement of elements. The group number shows the number of elements in the outer shell of the atoms.
The groups runs from 1 to 8. On the periodic table, elements that has more than 4 electrons in their outermost shell will have a valency of 8 less than the number of outermost electrons.
Write formulas for these hydrides without using subscripts, for example XH3. If no hydride forms, write "none".
for group I : NaH, KH,
group II : MgH2, CaH2,
group III: BH3, AlH3
Group 8 do not form hydrides because of their inertness.
What is the formula of the hydride formed by sulfur?
the hydride of sulfur is H₂S
What is the formula of the hydride formed by potassium ?
the hydride of potassium is KH
