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Nadya [2.5K]
4 years ago
12

A plane traveling from City a to City B travels X miles per hour for total of 4.5 hours that plane takes the same route on the r

eturn traveling 25 miles per hour faster for a total of 4.25 hours what is the total distance the plane travels?
Mathematics
1 answer:
Mkey [24]4 years ago
6 0
Your equation is gonna be
4.5a + 2.5b = 4.25

I forgot how lol but you gotta now solve for A and B.
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The length of a rectangular field is 4 m longer than its width.
Artyom0805 [142]
We know the perimeter is the sum of all sides. So lenght+length+width+width = 2length+2width.
Let's call the width x. If the length is 4m longer, then it's x+4.
We know the perimeter, so we can make an equation:
56=2x+2(x+4)
And solve from there:
56=2x+2x+8
56=4x+8
48=4x
48/4=x
x=12

The width, which is x, is 12 m. And the length, x+4, is 16 m.
You can check this is correct by calculating the perimeter using those values: 12+12+16+16=56.
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3 years ago
Y=-3x-19 substitution method slove for x
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You have to input the first part of the equation for me to solve the system of equality
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3 years ago
Bhaskar went for hiking with scouts’ team and there the scouts were given a task to build tents with the help of bamboos, ropes
dimulka [17.4K]

The triangles on Bhaskar's tent are similar triangles.  

  • <em>The length of IJ is 4.5 m </em>
  • <em>The applicable theorem is the mid-point theorem </em>
  • <em>The appropriate formula for area is the Heron's formula </em>
  • <em>The ratio of ABC to DEF is 1 : 9</em>

<u>(a) The length of IJ</u>

The given parameter are:

\mathbf{EF = 9m}

I and J are at the midpoint of DE and DF

The above highlight means that

\mathbf{IJ= \frac 12 \times EF} --- midpoint theorem

Substitute 9 for EF

\mathbf{IJ= \frac 12 \times 9m}

\mathbf{IJ= 4.5\ m}

<u>(b) The property used to find GH and IJ</u>

In (a), the midpoint theorem is used to calculate IJ

GH and IJ are corresponding sides of similar triangles,

So the midpoint theorem can also be used to calculate the length of GH

<u>(c) The area of the triangle</u>

For the given triangles, the lengths of the sides are known.

When side lengths are known, the formula to use for finding the triangle's area is the Heron's formula.

The Heron's formula is:

\mathbf{Area = \sqrt{s \times (s -a) \times (s - b) \times (s - c)}}

Where:

\mathbf{s = a + b + c}\\\mathbf{a,b,c \to sides\ of\ the\ triangle}

<u>(d): The ratio of the areas:</u>

For the small triangle, we have:

\mathbf{a= 3.8,\ b = 4,\ c = 3}

So, we have:

\mathbf{s = 3.8 + 4 + 3 = 10.8}

So, the area is:

\mathbf{Area = \sqrt{s \times (s -a) \times (s - b) \times (s - c)}}

\mathbf{A_{small} = \sqrt{10.8 \times (10.8 -3.8) \times (10.8 - 4) \times (10.8 - 3)}}

\mathbf{A_{small} = \sqrt{4009.824}}

For the big triangle, we have:

\mathbf{a= 11.4,\ b = 12,\ c = 9}

So, we have:

\mathbf{s = 11.4 + 12 + 9 = 32.4}

So, the area is:

\mathbf{Area = \sqrt{s \times (s -a) \times (s - b) \times (s - c)}}

\mathbf{A_{big} = \sqrt{32.4 \times (32.4 -11.4) \times (32.4 - 12) \times (32.4 - 9)}}

\mathbf{A_{big} = \sqrt{324795.744}}

The ratio of the small triangle to the big triangle is:

\mathbf{Ratio = A_{small} : A_{big}}

\mathbf{Ratio = \sqrt{4009.824}:\sqrt{324795.744}}

Divide by 4009.824

\mathbf{Ratio = \sqrt{1}:\sqrt{81}}

Take square roots

\mathbf{Ratio = 1 : 9}

Hence, the ratio of ABC to DEF is 1 : 9

Read more about similar triangles at:

brainly.com/question/24874611

7 0
3 years ago
The slope of a line will depend on which of the two points you choose to call (x1, y1) and which you choose to call (x2, y2) whe
lilavasa [31]

Answer:

  FALSE

Step-by-step explanation:

The slope can be calculated using any two points on the line in any order and the result will be the same.

3 0
4 years ago
Read 2 more answers
Find the volume.<br><br><br> 986 m3<br><br><br> 3,360 m3<br><br><br> 408 m3<br><br><br> 1,680 m3
Jobisdone [24]

Answer:

The volume is 1,680\ m^3

Step-by-step explanation:

we know that

The volume of a triangular prism is

V=BL

where

B is the area of the triangular base

L is the length of the prism

we have

B=\frac{1}{2}(28)(12)=168\ m^2

L=10\ m ----> perpendicular distance between the two triangular bases

substitute

V=(168)(10)=1,680\ m^3

4 0
3 years ago
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