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Soloha48 [4]
3 years ago
10

Name a pair of opposite rays whose end point is b

Mathematics
1 answer:
Neko [114]3 years ago
3 0

Answer:

Your answer would be G, since point G is opposite of point B, and is a ray.

Step-by-step explanation:


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Six more than 1/5 a number is 12. What is the number
suter [353]

Answer:

Step-by-step explanation:

let x be the number

6+1/5x=12

1/5x=12-6

1/5x=6

x=5*6

x=30

check: 6+(1/5*30)=6+6=12

8 0
2 years ago
Please help me with this problems before my head explodes
Orlov [11]

Answer:

1: c over 3

2: 9

3: 15 square root of 3

4: 5 + 2√6

Sorry but that's all I got

Step-by-step explanation:

4 0
3 years ago
What is the volume of this cone?
olchik [2.2K]

Answer:

The volume of the cone is approximately 453.0 cm³

Step-by-step explanation:

The volume of a cone is one third that of a cylinder with the same height and radius.  That gives us  1/3 πr²h, where r is radius and h is height.

However, we are not given the height of the cone, but the side length.  We can work out the height using the Pythagorean theorem, as we have a right triangle with the height, base radius, and length.  You may recall that the Pythagorean theorem states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of it's other two sides:

a^2 = b^2 + c^2

So we can find the height of the cone with that:

10.8^2 = 7.4^2 + h^2\\h^2 = 10.8^2 - 7.4^2\\h^2 = 116.64 - 54.76\\h^2 = 61.88\\h = \sqrt{61.88}\\h \approx  7.9

Now that we have the cone's height, we can solve for its volume:

v = \frac{1}{3} \pi r^2 h\\v = \frac{1}{3} \pi \times 7.4^2  \times 7.9\\v = \frac{1}{3} \pi \times 54.76 \times 7.9\\v = \frac{1}{3} \pi \times 432.6\\v = \pi \times 144.2\\v \approx 453.0 cm^3

5 0
3 years ago
Read 2 more answers
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<span>1 hour and 1/3rd of an hour.</span>
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2 years ago
An automobile tire at 30°C has a pressure of 3.00 atm. Temperature decreases to -5°C. Assume that there is no volume change in t
Usimov [2.4K]

Answer: decreases, 2.65 atm

Step-by-step explanation: it’s explained on edg.

4 0
3 years ago
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