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Oksanka [162]
2 years ago
14

Sin³xcosx+sinxcos³x=sinxcosx

Mathematics
1 answer:
Svetllana [295]2 years ago
6 0

Answer:

Step-by-step explanation:

sin^3xcosx+sinxcos^3x\\=sinx cosx(sin^2x+cos^2x)\\=sinx ~cosx(1)\\=sin~x~cos~x

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What is the measure of angle B?
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If is an angle bisector of ∠QOR and ∠QOP = 71°, then find the angle measure of ∠QOR. Question 8 options: A) 71° B) 142° C) 35.5°
zaharov [31]

Answer:  B. 142°.

Step-by-step explanation:

Given: OP is an angle bisector of ∠QOR and ∠QOP = 71°.

We know that an angle bisector divides an angle into two equal parts.

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8 0
3 years ago
ANSWER CORRECT FOR BRAINLIEST
monitta

Answer:

3 2 /5 ×3

change 3 2 /5 into an improper fraction

then you will get 17 /5

after that you say 17/5 ×3/1

=(17×3)/ (5x1)

=51/5 (51÷5)

=10.2/ 10 1/5

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