Answer:
Distributive Property : <em><u>a(b+c)= ab+ac</u></em>
<h3><u>(35-28x)</u> is the right answer.</h3>
You would need 7 freezer bags because you have to turn both fractions into improper fractions. to get that you have to multiply 15 by 4 and then add 3 so you get 63/1. Then for the next fraction, you multiply 4 by 2 and then add 1 so you get 9/1.
Now you have to divide the 2 fractions to find out how many freezer bags you need. So it would look like this. 63/1 divided by 9/1.
To divide fractions, you use the rule (keep, change, flip)
So you keep the first fraction 63/1 but you change to division sign to multiplication and lastly you flip the second fraction from 9/1 to 1/9 and now you multiply so it looks like this.
63/1 x 1/9 and you get 63/9 which equals 7 freezer bags.
I hope this helped you?? :)
Using the combination formula, it is found that he has 232 choices.
The order in which the sights are seen is not important, hence the <em>combination formula </em>is used to solve this question.
<h3>What is the combination formula?</h3>
is the number of different combinations of x objects from a set of n elements, given by:

In this problem, the choices are 8, 9, 10 or 11 sights from a set of 11, hence:

He has 232 choices.
You can learn more about the combination formula at brainly.com/question/25821700
Answer:
There should be 4 answers but pick the one closest to one side of the square.
Step-by-step explanation:
Assuming that the topping order is not important, you need to use the combination to solve this question. The number of toppings is 12 and then added 2, so the number will become: 12+2= 14 toppings
From 14 toppings, ian need to choose 3. The possible ways would be:
14C3= 14!/(14-3)!3!= 14*13*12/ 3*2= 364 possible ways