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3 years ago

35-4-2-13 O C5 ( 42) 13 o D( 64) -2-13

Mathematics

2 answers:

andre [41]3 years ago

8 0

Hm I think it’s D to

Radda [10]3 years ago

7 0

Hmmm it’s D I think?

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The 2017 senior class from Glen Haven High School raised funds for an end of the year party at Club Cool. It costs $3,000 to ren

Arlecino [84]

Answer:

12000 = 25x + 3000 is your equation

8 0

3 years ago

Read 2 more answers

9. 3x + 9y = 18<br> y = x + 2<br> Substitution method

777dan777 [17]

Answer:

x = 0

y = 2

Step-by-step explanation:

3x + 9y = 18 ---------eqn 1

y = x + 2---------eqn 2

Substitute eqn 2 into eqn 1, for the value of y

3x + 9( x + 2) = 18

3x + 9x + 18 = 18

12x + 18 = 18

12x = 18 -18

12x = 0

Divide both sides by 12 , to get the value of x.

12x/ 12 = 0/12

x = 0

Substitute x = 0 into eqn 2

y = x + 2

y = 0 +2

y = 2

Hint: to confirm the values

x = 0

y = 2

Let's take eqn 1 ,

3x + 9y = 18

3(0) + 9(2)

= 0 + 18

= 18

Correct

Let's take eqn 2

y = x + 2

Let's find y

y = 0 + 2

y = 2

Correct too

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3 years ago

Round 981,657 to the nearest ten thousand

MaRussiya [10]

981,657 = 980,000 to the nearest ten thousand

Hope it helps

5 0

3 years ago

2,7,26,101,400 what is the next number

Sedaia [141]

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3 years ago

FURTHER MATHEMATICS Use determinants to solve the systems of equation:

maw [93]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}2x+1y+2z&=&13\\1x+1y-2z&=&8\\1x+2y+1z&=&11\\\end{array}\right.\\\\\\\Delta=\left| \begin{array}{ccc}2&1&2\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\0&\frac{1}{2}&-3\\0&1&3\end{array}\right| =2*(\frac{3}{2}+3)=9\\\\$

$\Delta_1=\left| \begin{array}{ccc}13&1&2\\8&1&-2\\11&2&1\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\8&1&-2\\\frac{11}{2}& 1&\frac{1}{2}\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\-5&0&-4\\\frac{-5}{2}& 0&\frac{5}{2}\end{array}\right| \\\\=2*(-1)*(\frac{-25}{2}-\frac{20}{2}) =45\\$

$\Delta_2=\left| \begin{array}{ccc}2&13&2\\1&8&-2\\1&11&1\end{array}\right| \\\\\\=\left| \begin{array}{ccc}3&21&0\\3&30&0\\1&11&1\end{array}\right| \\\\\\=1*(90-63) =27\\$

$\Delta_3=\left| \begin{array}{ccc}2&1&13\\1&1&8\\1&2&11\end{array}\right| \\\\\\=\left| \begin{array}{ccc}0&-1&-3\\0&-1&-3\\1&2&11\end{array}\right| \\\\\\=0\\$

$\left\{\begin{array}{ccc}x=\dfrac{\Delta_1}{\Delta}=\dfrac{45}{9}=5\\\\y=\dfrac{\Delta_2}{\Delta}=\dfrac{27}{9}=3\\\\z=\dfrac{\Delta_3}{\Delta}=\dfrac{0}{9}=0\\\end{array}\right.$

8 0

3 years ago