Ask question

Ask question

All categories

3 years ago

10

What’s the least number of faces a polyhedron can have? And why?

1 answer:

Marysya12 [62]3 years ago

6 0

Answer:

The minimum number of faces a polyhedron can have is 4 faces.

Step-by-step explanation:

We know that a polyhedron is a shape surrounded by polygons. We also know that we need at least 3 sides to make a polygon. So, at the minimum a polyhedron can be made by using only triangular faces but in order to make a closed figure we need at least four triangular faces (which is a tetrahedron).

You might be interested in

What does is the value of x in this problem

nekit [7.7K]

Answer:

the value of x is 90.....

3 0

3 years ago

A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. if customers choose one salad, o

kobusy [5.1K]

$8\cdot5\cdot C(6,2)=40\cdot\dfrac{6!}{2!3!}=40\cdot\dfrac{4\cdot5\cdot6}{2}=2,400$

4 0

3 years ago

How many 5 pound bags of apples can be made from 400 apples each weighing 1/4 pound?

RUDIKE [14]

20 is the answer.........

7 0

3 years ago

Read 2 more answers

It is 2.3 km from Salma's house to the nearest mailbox. How far is it in meters?

Ivenika [448]

Answer:

2.3km in meters is 2300 Meters

Step-by-step explanation:

Multiply the length value by 1000

7 0

3 years ago

What is the midpoint of the line segment with endpoints(-2,-2) and (4,6)

Ann [662]

Answer:

The midpoint of points $(-2,-2)\ and\ (4,6)$ is $(1,2)$ .

Step-by-step explanation:

Given points are $(-2,-2)\ and\ (4,6)$ . We need to find the midpoint of the line segment.

The formula of finding midpoints between the point $(x_1,y_1)\ and\ (x_2,y_2)$ is

$(\frac{x_1+x_2}{2}),(\frac{y_1+y_2}{2})\ Equation(1)$

W have points $(x_1,y_1)=(-2,-2)$ . And $(x_2,y_2)=(4,6)$

Let us plug the value in Equation (1)

$(\frac{-2+4}{2} ),(\frac{-2+6}{2})$

$(\frac{2}{2}),(\frac{4}{2})\\ \\(1,2)$

So, the midpoint of points $(-2,-2)\ and\ (4,6)$ is $(1,2)$ .

3 0

4 years ago