A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:

a)F minimum

b) F maximum

c) Frequency resolution

Answer:

a) $Fmax=100Hz$

b) $Fmin=0Hz$

c) $F_r=0.0313$

Step-by-step explanation:

From the question we are told that:

Time $t=32sec$

Frequency $F=200Hz$

Segments $\mu=5$

Generally the equation for Frequency Range is mathematically given by

$Fmax=\frac{F}{2}$

$Fmax=100Hz$

Therefore

a) $Fmax=100Hz$

b) $Fmin=0Hz$

Generally the equation for Frequency Resolution is mathematically given by

$F_r=\frac{F}{N}$

Where

N=The Total dat points

N=Sampling Frequency *Time

$N=200*32$

$N=6400$

Therefore

$F_r=\frac{200}{6400}$

$F_r=0.0313$

6 0

3 years ago

Pls helpppp meeeeee :(

Alja [10]

Answer:

Sam

Step-by-step explanation:

Sam made a mistake when he said $10^2 -20$ . The steps should have been:

$2n^2-20=2(5)^2-20\\2(25)-20\\50-20=30$

You are supposed to square 5 first before multiplying 2. Sam multiplied by 2 first. The correct answer is 30.

7 0

3 years ago

a fish is 12 m below the surface of the ocean what is the elevation of sea bird is 28 m above the surface of the ocean what is t

ExtremeBDS [4]

Answer:

40m???

Step-by-step explanation:

7 0

3 years ago

Write an expression to match the description: 2 less than y

AveGali [126]

<h3>Answer:</h3>

y - 2

<h3>Step-by-step explanation:</h3>

You get 2 less than a value when you subtract 2 from that value.

3 0

3 years ago