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Roman55 [17]
3 years ago
15

Select the correct difference. 5d 2 + 4d - 3 less 3d 2 - 2d + 4

Mathematics
1 answer:
katen-ka-za [31]3 years ago
5 0
<span>5d^2 + 4d - 3 - (3d^2 - 2d + 4)
=</span>5d^2 + 4d - 3 - 3d^2 +  2d - 4
= 2d^2 + 6d - 7
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Write x^3/2 in radical form
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Answer:

Step-by-step explanation:

I think you meant x^(3/2).  This breaks down in at least two ways:

[x^3]^(1/2), or √(x^3)m or √x³), or

[x^(1/2)]^3 = (√x)^3

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3 years ago
Lee can read at a rate of 1,100words in 5 minutes.Write and solve a world problem that uses this information
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3 years ago
Determine the ratio in which the point (–6, m) divides the join of A(–3, –1) and B(–8, 9). Also, find the value of m.
PSYCHO15rus [73]

Answer:

Ratio = 3 : 2 and value of m = 5.

Step-by-step explanation:

We are given the end points ( -3,-1 ) and ( -8,9 ) of a line and a point P = ( -6,m ) divides this line in a particular ratio.

Let us assume that it cuts the line in k : 1 ratio.

Then, the co-ordinates of P = ( \frac{-8k-3}{k+1},\frac{9k-1}{k+1} ).

But, \frac{-8k-3}{k+1} = -6

i.e. -8k-3 = -6k-6

i.e. -2k = -3

i.e. k = \frac{3}{2}

So, the ratio is k : 1 i.e \frac{3}{2} : 1 i.e. 3 : 2.

Hence, the ratio in which P divides the line is 3 : 2.

Also, \frac{9k-1}{k+1} = m where k = \frac{3}{2}

i.e. m = \frac{\frac{9 \times 3}{2}-1}{\frac{3}{2}-1}

i.e. m = \frac{27-2}{3+2}

i.e. m = \frac{25}{5}

i.e. m = 5.

Hence, the value of m is 5.

4 0
3 years ago
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6 0
3 years ago
Question :-
DochEvi [55]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  +  \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } } \bigg ) {}^{2}  +  \bigg( \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}  + 2 \cdot \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  \cdot \sqrt{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{1}{7 +  \sqrt{5} }  + 7 +  \sqrt{5}  + 2

\qquad \sf  \dashrightarrow \: \dfrac{49 + 7 \sqrt{5} + 7 \sqrt{5} + 5 + 14 + 2 \sqrt{5}   }{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{68+ 16 \sqrt{5}    }{7 +  \sqrt{5} }

5 0
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