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4 years ago

Which of the following energy changes occurs as a bow is drawn and released?

2 answers:

8 0

3. elastic potential to kinetic
Mechanical energy is the top suject while it has two types: Kinetic energy which is the energy in motion and potential energy which is the energy in reserve. The measure of both energy in motion and reserve is called Joules. Joules then is the International System of Measurement unit for energy, this is mainly used to account for scaling energy in all aspects.

Sonbull [250]4 years ago

6 0

Answer: The correct answer is 3.

Explanation: As the bow is drawn and released, it will experience a change in elastic potential energy to kinetic energy.

Elastic potential energy is defined as the amount of potential energy which is stored as a result of the deformation of the object which has some elasticity in it. For Example: Stretching of a spring, Drawing of a bow, etc..

Kinetic energy is the energy of the object which is possessed as a result of its motion.

When the bow is drawn, it first had some elastic potential energy and when it is released it had some kinetic energy in it.

Conclusion: The correct answer is 3.

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1.8x10^24 atoms is How many atoms are in 1.50 moles of fluorine gas

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3 years ago

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3 years ago

In most lewis dot structures of neutral compounds, carbon as the central atom will be bound to a maximum of how many atoms, nitr

Fittoniya [83]

The total number of elements that one particular element can bond to can be determined by simply drawing the Lewis structure of the element.

Place the chemical symbol
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3 years ago

Convert 6.7 x 1024 molecules of nitrogen dioxide into grams.

BlackZzzverrR [31]

Answer:

510 g NO₂

General Formulas and Concepts:

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Reading the Periodic Table
Writing Compounds
Using Dimensional Analysis

Explanation:

Step 1: Define

6.7 × 10²⁴ molecules NO₂ (Nitrogen dioxide)

Step 2: Define conversions

Avogadro's Number

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of NO₂ - 14.01 + 2(16.00) = 46.01 g/mol

Step 3: Use Dimensional Analysis

$6.7 \cdot 10^{24} \ molecules \ NO_2(\frac{1 \ mol \ NO_2}{6.022 \cdot 10^{23} \ molecules \ NO_2} )(\frac{46.01 \ g \ NO_2}{1 \ mol \ NO_2} )$ = 511.901 g NO₂

Step 4: Check

We are given 2 sig figs. Follow sig fig rules.

511.901 g NO₂ ≈ 510 g NO₂

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