Let's assume that CH₄ has ideal gas behavior.
Then we can use ideal gas formula,
PV = nRT
Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol⁻¹ K⁻¹) and T is temperature in Kelvin.
P = 1 atm = 101325 Pa
V = 1.50 L = 1.50 x 10⁻³ m³
n = ?
R = 8.314 J mol⁻¹ K⁻¹
T = 0 °C = 273 K
By substitution,
101325 Pa x 1.50 x 10⁻³ m³ = n x 8.314 J mol⁻¹ K⁻¹ x 273 K
n = 0.0669 mol
Hence, moles of CH₄ = 0.0669 mol
Moles = mass / molar mass
Molar mass of CH₄ = 16 g mol⁻¹
Mass of CH₄ = moles x molar mass
= 0.0669 mol x 16 g mol⁻¹
= 1.0704 g
Hence, mass of CH₄ in 1.50 L at STP is 1.0704 g
<span>D.) Oxygen would acquire a stable arrangement of electrons by bonding with two atoms of "Magnesium"
[ As Mg has 2 extra electrons & their size are quite similar ]
Hope this helps!</span>
Answer:
the farther they are the longer there cycle is. closer they are shorter time.
Answer:
99 L
Explanation:
Step 1: Given data
Moles of nitrogen: 4.4 moles
Step 2: Calculate the volume occupied by 4.4 moles of nitrogen
The volume occupied by a gas depends on other conditions such as pressure (P) and temperature (T). If we have this information, we can calculate the volume of the gas using the ideal gas condition.
P × V = n × R × T
Since the task doesn't inform the conditions, we can assume it is under standard pressure (1 atm) and temperature (273.15 K). At STP, 1 mole of any gas occupies 22.4 L.
4.4 mol × 22.4 L/1 mol = 99 L
<span>Cleavage because the thin sheets will break apart easily in one direction but not the other.</span>