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Liono4ka [1.6K]
3 years ago
15

Hhhhhhhhelpp meeeeeee

Mathematics
1 answer:
devlian [24]3 years ago
5 0

Answer:

with what?

Step-by-step explanation:

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The volume of a rectangular prism is b3 + 8b2 + 19b + 12 cubic units, and its height is b + 3 units. The area of the base of the
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Given:

The volume of the rectangular prism is 

b^{3}+8 b^{2} +19b+12,

the height is h=(b+3)

1. The volume of a rectangular prism is (base area)*height

also, notice that the volume is a third degree polynomial, the height is a 1st degree polynomial, so the base area must be a 2nd degree polynomial, whose coefficients we don't know yet.
Let this quadratic polynomial be (mb^{2}+nb+k)

 
2

b^{3}+8 b^{2} +19b+12=(mb^{2}+nb+k)*(b+3)


notice that  b^{3} is the product of the largest 2 terms: mb^{2} and b, so m must be 1

also, notice that 12 is the product of the constants, k and 3

so k*3=12, this means k=4

3
we write the above equality again:

b^{3}+8 b^{2} +19b+12=(b^{2}+nb+4)*(b+3)


(b^{2}+nb+4)(b+3)= b^{3}+3 b^{2} +nb^{2}+3nb+4b+12

== b^{3}+(n+3)b^{2}+(3n+4)b+12


4
now compare the coefficient with the left side:

8 b^{2}=(n+3)b^{2}

8=n+3

n=5


substituting n=5: 

the base area is b^{2}+5b+4

Answer: b^{2}+5b+4


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Step-by-step explanation:

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