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Artemon [7]
3 years ago
6

Write rational numbers between 0 and 1

Mathematics
1 answer:
RoseWind [281]3 years ago
3 0

Step-by-step explanation:

0/1 , 1/1

Multiply there denominators with any number...

0/1×60=0/60

1/1××60=60/60

Now,

You have many choices...

1/60,10/60,30/60,2/60,5/60........so on....

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Which of the following three-dimensional figures is formed when an equilateral triangle is rotated around the x-axis of the coor
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I think that the D. CONE is the three-dimensional figure that will be formed when an equilateral triangle is rotated around the x-axis of the coordinate plane.

<span>A sphere is defined as the set of all points in space that are a fixed distance from a common point, the center.
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5 0
3 years ago
Read 2 more answers
4 coffees and 12 lattes. Costs $61
Gala2k [10]

Answer:

Cost of a coffee is <u>$2.5</u> and cost of a latte is <u>$4.25.</u>

Step-by-step explanation:

Let cost of 1 coffee be 'c' and cost of 1 latte be 'l' dollars.

Given:

4 coffees and 12 lattes cost $61.

12 coffees and 7 lattes cost $59.75.

∵ 1 coffee cost = c

∴ 4 coffees cost = 4c and 12 coffee cost = 12c

∵ 1 latte cost = l

∴ 12 lattes cost = 12l and 7 lattes cost = 7l

Now, as per question:

4c+12l=61-----1\\12c+7l=59.75----2

Now, multiplying equation (1) by -3 and adding the result to equation (2). This gives,

-3(4c+12l)=-3(61)\\\\-12c-36l=-183\\12c+7l=59.75\\+\\----------\\0-29l=-123.25\\\\l=\frac{-123.25}{-29}=\$4.25

Now, plug in the value of 'l' in equation 1 to solve for 'c'. This gives,

4c+12(4.25)=61\\\\4c+51=61\\\\4c=61-51\\\\4c=10\\\\c=\frac{10}{4}=\$2.5

Therefore, cost of a coffee is $2.5 and cost of a latte is $4.25.

4 0
3 years ago
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storchak [24]
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Factor<span> by </span>perfect square<span> rule. 
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Replace into larger expression<span>. 
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3 0
3 years ago
7n-4=31 I need help to solve n
vfiekz [6]
7n-4=31
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8 0
3 years ago
If a club charges dues of $200 a year, it will have 50 members. For each $5 it raises its dues, it loses a member. USE AN EQUATI
Vikentia [17]

Answer:

The value is      y  =  \$ 225

Step-by-step explanation:

From the question we are told that

   The amount charge per year is  k  =  \$ 200

   The  number of members it will have at this amount is  n  =  50

   The amount amount increase that will lead to the loss of a single member is   z =  \$ 5

        Generally the total amount the club would obtain from  its members is mathematically represented as

      I  =  Amount \  due\ paid *  Number \  of members

Now let x denote the number of member lost

Hence

      I  =  (k + zx) (n-x )

=>    I  =  (200 + 5x) (50-x )

=>  I  = 10000+50x-5x^2

Thus the number of members that be removed to  give the maximum  income from dues is obtained by differentiating the above equation and equating it to zero

           \frac{dI}{dx}  =  50-10x

=>         x   =  5

So from  I  =  (200 + 5x) (50-x ) we have

          I  =  (200 + 5 (5)) (50-5 )

           I  = \$ 10125

So the amount the club should charge is    

         y  =  \frac{10125}{50 - 5}

         y  =  \$ 225

         

7 0
3 years ago
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