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3 years ago

Give an example of an amorphous solid.... PLS HELP ON THIS

1 answer:

6 0

Some examples of amorphous solids include rubber, plastic, and gels. Glass is a very important amorphous solid that is made by cooling a mixture of materials in such a way that it does not crystallize. Glass is sometimes referred to as a supercooled liquid rather than a solid.

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Which of these describes an exothermic reaction?

solong [7]

In Endothermic reactions, energy is absorbed.

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3 years ago

Read 2 more answers

A 581.2 mL sample of carbon dioxide was heated to 347 K.

svetlana [45]

Answer:

The temperature at 581.2 mL volume was 242.8 K.

Explanation:

Using Charle's law

$\frac {V_1}{T_1}=\frac {V_2}{T_2}$

Given ,

V₁ = 581.2 mL

V₂ = 830.5 mL

T₁ = ?

T₂ = 347 K

Using above equation as:

$\frac {581.2\ mL}{T_1}=\frac {830.5\ mL}{347\ K}$

$T_1=\frac{581.2\times 347}{830.5}\ K=242.8\ K$

The temperature at 581.2 mL volume was 242.8 K.

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4 years ago

What is an effect of electrostatic forces inside the nucleus?

Ivahew [28]

Answer: A
The protons in the nucleus repel each other

Explanation:
the number of protons inside a nucleus increases the electrostatic repulsion between protons increase reducing the binding energy. Thus the electrostatic force determines the stability of a nuclear configuration

3 0

3 years ago

The K sp for barium fluoride, BaF2, is 2.45 × 10-5. What is the molar solubility of barium fluoride?

lilavasa [31]

Answer: The molar solubility of barium fluoride is 0.0183 moles/liter.

Explanation:

The equation for the reaction will be as follows:

$BaF_2\rightarrow Ba^{2+}+2F^$

By Stoichiometry,

1 mole of $BaF_2$ gives 2 moles of $F^-$ and 1 mole of $Ba^{2+}$

Thus if solubility of $BaF_2$ is s moles/liter, solubility of $Ba^{2+}$ is s moles/liter and solubility of $F^-$ is 2s moles/liter

Therefore,

$K_sp=[Ba^{2+}][F^{-}]^2$

$2.45\times 10^{-5}=[s][2s]^2$

$4s^3=2.45\times 10^{-5}$

$s^3=6.12\times 10^{-6}moles/liter$

$s=0.0183moles/liter$

Thus the molar solubility of barium fluoride is 0.0183 moles/liter.

8 0

4 years ago

Given the reaction that occurs in an electrochemical cell: Zn(s) + CuSO4(aq) --> ZnSO4(aq) + Cu(s) During this reaction, the

liq [111]

Zn⁰(s) + CuSO4(aq) --> Zn²⁺SO4²⁻(aq) + Cu(s)

Zn⁰ --- in free elements oxidation number is 0.
Zn²⁺SO4²⁻ ---- ionic compound , it has ion Zn²⁺, so oxidation number here is +2.
The oxidation number of Zn changes from 0 to +2.

8 0

3 years ago