Given the reaction that occurs in an electrochemical cell: Zn(s) + CuSO4(aq) --> ZnSO4(aq) + Cu(s) During this reaction, the

Question

Nastasia [14]

3 years ago

11

Given the reaction that occurs in an electrochemical cell: Zn(s) + CuSO4(aq) --> ZnSO4(aq) + Cu(s) During this reaction, the

oxidation number of Zn changes from

Chemistry

1 answer:

liq [111] · Answer 1 · 2022-04-09T15:38:34+03:00

liq [111]3 years ago

8 0

<span>Zn⁰(s) + CuSO4(aq) --> Zn²⁺SO4²⁻(aq) + Cu(s)

</span>Zn⁰ --- in free elements oxidation number is 0.
Zn²⁺SO4²⁻ ---- ionic compound , it has ion Zn²⁺, so oxidation number here is +2.
<span>The oxidation number of Zn changes from 0 to +2.</span>