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Nastasia [14]
3 years ago
11

Given the reaction that occurs in an electrochemical cell: Zn(s) + CuSO4(aq) --> ZnSO4(aq) + Cu(s) During this reaction, the

oxidation number of Zn changes from
Chemistry
1 answer:
liq [111]3 years ago
8 0
<span>Zn⁰(s) + CuSO4(aq) --> Zn²⁺SO4²⁻(aq) + Cu(s)

</span>Zn⁰ --- in free elements oxidation number is 0.
Zn²⁺SO4²⁻ ---- ionic compound , it has ion Zn²⁺, so oxidation number here is +2.
<span>The oxidation number of Zn changes from 0 to +2.</span>
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Answer:

107.9g

Explanation:

Given parameters:

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4 0
3 years ago
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