1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tamaranim1 [39]
3 years ago
9

Which of the following points is a solution to the system of inequalities?HURRY ITS MY EXAM

Mathematics
1 answer:
vazorg [7]3 years ago
8 0

Answer:

THANKS FOR THE FREE POINTS!

Step-by-step explanation:

u cant report me bc it’s against guidelines to use this for exams or timed tests

You might be interested in
A cone-shape mountain of garden soil is dumped on a flat surface. If the diameter of the mountain is 12 cm and its volume is 480
sukhopar [10]

Answer:

Step-by-step explanation:

400cm

4 0
3 years ago
Read 2 more answers
The graph of y=4x has been shifted up 3 units.what is it’s new equation
Katyanochek1 [597]

I think it’s y=4x+3

4 0
3 years ago
A 95% confidence interval was computed using a sample of 16 lithium batteries, which had a sample mean life of 645 hours. The co
polet [3.4K]

Answer:

Step-by-step explanation:

Hello!

The mean life of 16 lithium batteries was estimated with a 95% CI:

(628.5, 661.5) hours

Assuming that the variable "X: Duration time (life) of a lithium battery(hours)" has a normal distribution and the statistic used to estimate the population mean was s Student's t, the formula for the interval is:

[X[bar]±t_{n-1;1-\alpha /2}* \frac{S}{\sqrt{n} }]

The amplitude of the interval is calculated as:

a= Upper bond - Lower bond

a= [X[bar]+t_{n-1;1-\alpha /2}* \frac{S}{\sqrt{n} }] -[X[bar]-t_{n-1;1-\alpha /2}* \frac{S}{\sqrt{n} }]

and the semiamplitude (d) is half the amplitude

d=(Upper bond - Lower bond)/2

d=([X[bar]+t_{n-1;1-\alpha /2}* \frac{S}{\sqrt{n} }] -[X[bar]-t_{n-1;1-\alpha /2}* \frac{S}{\sqrt{n} }] )/2

d= t_{n-1;1-\alpha /2}* \frac{S}{\sqrt{n} }

The sample mean marks where the center of the calculated interval will be. The terms of the formula that affect the width or amplitude of the interval is the value of the statistic, the sample standard deviation and the sample size.

Using the semiamplitude of the interval I'll analyze each one of the posibilities to see wich one will result in an increase of its amplitude.

Original interval:

Amplitude: a= 661.5 - 628.5= 33

semiamplitude d=a/2= 33/2= 16.5

1) Having a sample with a larger standard deviation.

The standard deviation has a direct relationship with the semiamplitude of the interval, if you increase the standard deviation, it will increase the semiamplitude of the CI

↑d= t_{n-1;1-\alpha /2} * ↑S/√n

2) Using a 99% confidence level instead of 95%.

d= t_{n_1;1-\alpha /2} * S/√n

Increasing the confidence level increases the value of t you will use for the interval and therefore increases the semiamplitude:

95% ⇒ t_{15;0.975}= 2.131

99% ⇒ t_{15;0.995}= 2.947

The confidence level and the semiamplitude have a direct relationship:

↑d= ↑t_{n_1;1-\alpha /2} * S/√n

3) Removing an outlier from the data.

Removing one outlier has two different effects:

1) the sample size is reduced in one (from 16 batteries to 15 batteries)

2) especially if the outlier is far away from the rest of the sample, the standard deviation will decrease when you take it out.

In this particular case, the modification of the standard deviation will have a higher impact in the semiamplitude of the interval than the modification of the sample size (just one unit change is negligible)

↓d= t_{n_1;1-\alpha /2} * ↓S/√n

Since the standard deviation and the semiamplitude have a direct relationship, decreasing S will cause d to decrease.

4) Using a 90% confidence level instead of 95%.

↓d= ↓t_{n_1;1-\alpha /2} * S/√n

Using a lower confidence level will decrease the value of t used to calculate the interval and thus decrease the semiamplitude.

5) Testing 10 batteries instead of 16. and 6) Testing 24 batteries instead of 16.

The sample size has an indirect relationship with the semiamplitude if the interval, meaning that if you increase n, the semiamplitude will decrease but if you decrease n then the semiamplitude will increase:

From 16 batteries to 10 batteries: ↑d= t_{n_1;1-\alpha /2} * S/√↓n

From 16 batteries to 24 batteries: ↓d= t_{n_1;1-\alpha /2} * S/√↑n

I hope this helps!

4 0
3 years ago
If f(x) = 2x+1/x-4 what is the value of f^-1(3)
Olegator [25]

Answer:

f^-1(3) = 1.719 or  f^-1(3) = 0.149

Step-by-step explanation:

for inverse function x and y coordinates are flipping so graph the function and find for what x - coordinate y- coordinate = 3

in case that f(x) = 2x + \frac{1}{x-4} than f^-1(3) = 1.719

in case that f(x) = 2x + \frac{1}{x} -4 than f^-1(3) = 0.149

3 0
3 years ago
Evaluate the following expressions for p = 21.<br><br> a) 3p + 52<br> b) 432 - 2p
Reil [10]
A) the answer is 115
B)390
7 0
3 years ago
Read 2 more answers
Other questions:
  • Samantha sends her son, Barry, to a preschool center on certain days. The cost of preschool is $45 per day along with a fixed mo
    14·1 answer
  • Evaluate 5214 ÷ 39 ​
    5·1 answer
  • Show a number line 2/3 3/3
    13·1 answer
  • GUYS I NEED FIVE SENTECES!!!! IM GIVING BRAINLIEST!
    13·1 answer
  • (2.5, 1.3, 2.2, x), mean = 1.8
    13·1 answer
  • Which relations represent a function?
    10·1 answer
  • A number line contains points Q, R, S, and T. Point Q is on the coordinate 4, R is on the coordinate 8, S is on the coordinate 9
    13·1 answer
  • Does American accelerationism have human rights? # accelerationism
    5·1 answer
  • Can any one help with y = 2x + 4
    14·2 answers
  • Collection of domestic animals is a set. However, a collection of big domestic animal is not a set. How do you justify this stat
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!