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bearhunter [10]
3 years ago
5

How do we write a set -builder method ?​

Mathematics
1 answer:
Katena32 [7]3 years ago
8 0

Answer: 6(1,2,3)

Step-by-step explanation:

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anygoal [31]
26 and 151? Because im confused to death srry if it doesnt help. I tryed.
3 0
3 years ago
Angelo thinks of a number, multiplies it by 5 and subtracts 8.His number is 47,wite as an equation in y and solve to find Angelo
Inessa05 [86]

Answer:

<h3>y*5-8=47</h3><h3>y*5=47+8</h3><h3>y*5=55</h3><h3>y=55/5</h3><h3>y=11</h3>
7 0
3 years ago
Question 9
True [87]

Answer:

17

Step-by-step explanation:

m<1 = (4x + 2)

m<3 = (5x - 15)

To find the value of x, we need to generate an equation.

<1 and <3 are vertical angles. Vertical angles are congruent. Therefore:

m<1 = m<3

(4x + 2) = (5x - 15)

Use this equation to solve for x

4x + 2 = 5x - 15

Subtract 5x from both sides

4x + 2 - 5x = 5x - 15 - 5x

-x + 2 = -15

Subtract 2 from both sides

-x + 2 - 2 = -15 - 2

-x = -17

Divide both sides by -1

x = 17

5 0
2 years ago
Find the complete factored form of the polynomial -24a6b4-40a3
Naddik [55]

For this case we have the following polynomial:

-24a ^ 6b ^ 4-40a ^ 3

We must find the greatest common factor of the terms of the polynomial.

The GCF of the coefficients is given by:

24 = 3 * 8\\40 = 5 * 8

Then we look for the GFC of the variables:

We have then:

a ^ 6 = a ^ 3a ^ 3\\a ^ 3 = a ^ 3

Finally rewriting we have: -24a ^ 6b ^ 4-40a ^ 3 = -8a ^ 3 (3a ^ 3b ^ 4 + 5)

Answer:

the complete factored form of the polynomial is:

-8a ^ 3 (3a ^ 3b ^ 4 + 5)

8 0
3 years ago
For all values of x
Yuliya22 [10]

Answer:

A.) gf(x) = 3x^2 + 12x + 9

B.) g'(x) = 2

Step-by-step explanation:

A.) The two given functions are:

f(x) = (x + 2)^2 and g(x) = 3(x - 1)

Open the bracket of the two functions

f(x) = (x + 2)^2

f(x) = x^2 + 2x + 2x + 4

f(x) = x^2 + 4x + 4

and

g(x) = 3(x - 1)

g(x) = 3x - 3

To find gf(x), substitute f(x) for x in g(x)

gf(x) = 3( x^2 + 4x + 4 ) - 3

gf(x) = 3x^2 + 12x + 12 - 3

gf(x) = 3x^2 + 12x + 9

Where

a = 3, b = 12, c = 9

B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)

To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula

Y = 3x + 3

X = 3y + 3

Make y the subject of formula

3y = x - 3

Y = x/3 - 3/3

Y = x/3 - 1

Therefore, g'(x) = x/3 - 1

For g'(12), substitute 12 for x in g' (x)

g'(x) = 12/4 - 1

g'(x) = 3 - 1

g'(x) = 2.

5 0
2 years ago
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