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bearhunter [10]
3 years ago
5

How do we write a set -builder method ?​

Mathematics
1 answer:
Katena32 [7]3 years ago
8 0

Answer: 6(1,2,3)

Step-by-step explanation:

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Evaluate the expression for the given value of each variable.
makkiz [27]
I believe the answer should be 77
5 0
3 years ago
Solve the system using the substituiton method<br> branliest offered<br> 3x-7y=10<br> x-4y=5
fiasKO [112]
Hi there!

To solve this problem using substitution, we need to set x equal to a value and substitute it into the other equation.

Since
x - 4y = 5,
x = 5 + 4y

3x - 7y = 10
3(5 + 4y) - 7y = 10
15 + 12y - 7y = 10
15 + 5y = 10
5y = -5
y = -1

Now that we know y is -1, we can substitute it back into the equation to find x:

y = -1
x - 4y = 5
x - 4(-1) = 5
x - (-4) = 5
x + 4 = 5
x = 1

So, your answers are x = 1 and y = -1.

Hope this helps!
6 0
3 years ago
GUYS PLEASE HELP! AND SOLVE THIS WITH ME!
tino4ka555 [31]

Answer:

Step-by-step explanation:

* 33/100 = .3(bar)

* 23/50 =.46

* 6/8 = .75

* 1/3 = .3(bar)

* 7/10 =.7

* 21/81 = .26

* 3/16 = .1875

* 7/20 =.35

5 0
3 years ago
P and Q are two points on the line x - y + 1 = 0 and are at distance 5 from the origin. Find the area of the triangle OPQ. ​
Alecsey [184]

Answer:

P and Q are two points on the line x-y+1=0 and are at a distant of 5 units from the origin. Find the area of triangle POQ.

Step-by-step explanation:

P and Q are the intersection points of

x-y+1 = 0 and the circle x^2 + y^2 = 25

sub y = x+1 into the circle

x^2 + (x+1)^2 = 25

x^2 + x^2 + 2x + 1 - 25 = 0

x^2 + x - 12 = 0

(x+4)(x-3) = 0

x = 3 or x = -4

y = 4 or y = -3

so P(3,4) and Q(-4,3) are our two points

Height of triangle.

h = |0 - 0 + 1|/√2 = 1/√2

PQ = √( (-7)^2 + 1^2) = √50 = 5√2

area POQ = (1/2)(1/√2)(5√2) = 5/2 square units

hope this helped

7 0
2 years ago
Plz I need help on #12
Lorico [155]

Answer:

C its C

Step-by-step explanation:

7 0
3 years ago
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