Answer:
y= 5-8x
Step-by-step explanation:
See image below:)
Answer:
ha ya
Step-by-step explanation:
Answer:
![\tan(22.6)=\frac{a}{12}](https://tex.z-dn.net/?f=%5Ctan%2822.6%29%3D%5Cfrac%7Ba%7D%7B12%7D)
Step-by-step explanation:
We know that
. Rounding the value of b as asked in the problem gives b=12.
From the right-triangle definition of cosine, b must be the adjacent side to the angle 22.6º and the hypothenuse of the triangle must be 3.
Then, a is the opposite side of the angle 22.6º therefore using the definition of sine,
. Solving for a, we obtain
.
We conclude that
.
Answer:
41 miles
Step-by-step explanation:
The first week, which is 7 days, Adam walked 2 miles a day. So, we have the multiplication equation: 2 * 7 = 14 miles.
For the next 9 days, Adam walked 3 miles per day. So, we have the multiplication equation: 3 * 9 = 27 miles.
Now, we just add these two values together:
14 + 27 = 41 miles
Thus, the answer is 41 miles.
Hope this helps!
Answer:
5 feet
Step-by-step explanation:
We are given that
Width of rectangular pool=b=30 feet
Length of rectangular pool=l=40 feet
Area of rectangle=![l\times b](https://tex.z-dn.net/?f=l%5Ctimes%20b)
Using the formula
Area of rectangular pool=![30\times 40=1200ft^2](https://tex.z-dn.net/?f=30%5Ctimes%2040%3D1200ft%5E2)
Total area enclosed within the perimeter of the deck=![2000ft^2](https://tex.z-dn.net/?f=2000ft%5E2)
Width of deck=x ft
Length of rectangular pool including wooden deck=40+2x ft
Width of rectangular pool including wooden deck=30+2x ft
Area of rectangular pool including wooden deck=![(40+2x)(30+2x)](https://tex.z-dn.net/?f=%2840%2B2x%29%2830%2B2x%29)
According to question
![(40+2x)(30+2x)=2000](https://tex.z-dn.net/?f=%2840%2B2x%29%2830%2B2x%29%3D2000)
![40(30)+2x(30)+40(2x)+2x(2x)=2000](https://tex.z-dn.net/?f=40%2830%29%2B2x%2830%29%2B40%282x%29%2B2x%282x%29%3D2000)
![1200+60x+80x+4x^2=2000](https://tex.z-dn.net/?f=1200%2B60x%2B80x%2B4x%5E2%3D2000)
![140x+4x^2=2000-1200=800](https://tex.z-dn.net/?f=140x%2B4x%5E2%3D2000-1200%3D800)
![4x^2+140x-800=0](https://tex.z-dn.net/?f=4x%5E2%2B140x-800%3D0)
(Dividing by 4 on both sides)
![x^2+40x-5x-200=0](https://tex.z-dn.net/?f=x%5E2%2B40x-5x-200%3D0)
![x(x+40)-5(x+40)=0](https://tex.z-dn.net/?f=x%28x%2B40%29-5%28x%2B40%29%3D0)
![(x+40)(x-5)=0](https://tex.z-dn.net/?f=%28x%2B40%29%28x-5%29%3D0)
![x+40=0](https://tex.z-dn.net/?f=x%2B40%3D0)
![x=-40](https://tex.z-dn.net/?f=x%3D-40)
It is not possible because width cannot be negative it is always natural number.
![x-5=0\implies x=5](https://tex.z-dn.net/?f=x-5%3D0%5Cimplies%20x%3D5)
Hence, the width of the deck=5 ft