Ask question

Ask question

All categories

4 years ago

15

Are there any clusters or outliers in the scatter plot?

2 answers:

IrinaVladis [17]4 years ago

5 0

The correct answer is D because there is one area that is a cluster (bundle of dots in one area) and one outlier (away from all the other points; irrelevant).

ElenaW [278]4 years ago

4 0

Answer:

A) There is one cluster and one outlier.

Step-by-step explanation:

We are given the following information in the question:

We are given a scatter plot.

Sometimes the data points in a scatter plot form distinct groups. These groups are called clusters. A cluster is formed when several data points lie in a small interval.
An outlier is defined as a data point that can be differentiated from the rest of the data. It is an observation that lies an abnormal distance from other values in a random sample from a population.

When observed, the given scatter plot has one cluster and one outlier.

Hence, option A) is the correct answer.

You might be interested in

What is the volume of the cone in terms of π

jolli1 [7]

Answer:

Step-by-step explanation:

V=πr2h

3

r Radius

h Height

4 0

3 years ago

The table shows information about the number of sweatshirts sold and money collected at a fundraiser for school athletic program

Murljashka [212]

…………………………………………….not really sure about the last question

6 0

3 years ago

Help on this question please

telo118 [61]

Answer:

$33.00

Step-by-step explanation:

Total number of members = 45+30 = 75

Total cost for making name tags

= 75 * (0.44)

= $33.00

6 0

3 years ago

Find all solutions of the given system of equations (If the system is infinite many solution, express your answer in terms of x)

lisov135 [29]

Answer:

(a) The system of the equations $\left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right.$ has no solution.

(b) The system of the equations $\left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right.$ has many solutions $y=\frac{2x}{3}-\frac{5}{3}$

Step-by-step explanation:

(a) To find the solutions of the following system of equations $\left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right.$ you must:

Multiply $2x-3y=3$ by 2:

$\begin{bmatrix}4x-6y=6\\ 4x-6y=3\end{bmatrix}$

Subtract the equations

$4x-6y=3\\-\\4x-6y=6\\------\\0=-3$

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system $\left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right.$ you must:

Isolate x for $4x-6y=10$

$x=\frac{5+3y}{2}$

Substitute $x=\frac{5+3y}{2}$ into the second equation

$16\cdot \frac{5+3y}{2}-24y=40\\8\left(3y+5\right)-24y=40\\24y+40-24y=40\\40=40$

The system has many solutions.

Isolate y for $4x-6y=10$

$y=\frac{2x}{3}-\frac{5}{3}$

3 0

3 years ago

Iteru [2.4K]

Answer:

374/105.

Step-by-step explanation:

1/3 of 8 * 2/7

= 1/3 * 8 * 2/7

= 8/3 * 2/7

= 16/21.

2/5 of 7

= 2/5 * 7

= 14/5.

Adding 16/21 + 14/5

= 80 / 105 + (14*21) / 105

= 80/105 + 294/105

= 374/105.

8 0

3 years ago