Answer:
6 units on edg 2020
Step-by-step explanation:
Luis = 6/7
Marrisa = 5/9
Federico = 11/10 = 1 1/10
Greatest fraction = 1 1/10
Answer: Frederico raised the most.
Answer:
y = ⅔x - 5
Step-by-step explanation:
To write the equation, find the slope (m), to enable you write the equation of the line in point-slope form given a point, (-3, -7) that the line passes through.
Since the line is parallel to 2x - 3y = 24,, it would have the same slope (m) value.
Rewrite 2x - 3y = 24 in slope-intercept form.
Thus:
2x - 3y = 24
-3y = -2x + 24
y = ⅔x - 12
The slope of 2x - 3y = 24 is ⅔. Therefore, the line that is parallel to 2x - 3y = 24 is also ⅔.
To write the equation of the line, substitute (a, b) = (-3, -7) and m = ⅔ into y - b = m(x - a)
Thus:
y - (-7) = ⅔(x - (-3))
y + 7 = ⅔(x + 3)
y + 7 = ⅔x + 2
y = ⅔x + 2 - 7
y = ⅔x - 5
Problem 4
a)
MR = AG is a true statement because MARG is an isosceles trapezoid. The diagonals of any isosceles trapezoid are always the same length.
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b)
MA = GR is false. Parallel sides in a trapezoid are never congruent (otherwise you'll have a parallelogram).
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c)
MR and AG do NOT bisect each other. The diagonals bisect each other only if you had a parallelogram.
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Problem 5
a)
LC = AJ (nonparallel sides of isosceles trapezoid are always the same length)
x^2 = 25
x = sqrt(25)
<h3>x = 5</h3>
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b)
LU = 25
UC = 25 because point U cuts LC in half
LC = LU+UC = 25+25 = 50
AJ = LC = 50 (nonparallel sides of isosceles trapezoid are always the same length)
AS = (1/2)*AJ
AS = (1/2)*50
<h3>AS = 25</h3>
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c)
angle LCA = 71
angle CAJ = 71 (base angles of isosceles trapezoid are always congruent)
(angleAJL)+(angleCAJ) = 180
(angleAJL)+(71) = 180
angle AJL = 180-71
<h3>angle AJL = 109 </h3>
