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Lubov Fominskaja [6]
3 years ago
6

A store is giving out cards labeled 1 through 10 when customers enter the store. If the card is an even​ number, you get a 10​%

discount on your purchase that day. If the card is an odd number greater than​ 6, you get a 40​% discount.​ Otherwise, you get a 20​% discount. The table shows the results of 400 customers. What is the relative frequency for each​ discount? Use pencil and paper. If the manager of the store wants approximately half of the customers to receive the 20​% ​discount, does this seem like an appropriate​ method? Explain.
Mathematics
1 answer:
Amanda [17]3 years ago
8 0

The answer would be A. 1 1/5

48/40 = 1 8/40

1 8/40 Simplify to 1 1/5

Hope this helps!
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A taxi service charges a flat fee of $1.25 and $0.75 per mile. If Henri has $14.00, which of the following shows the number of m
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Henri has enough to pay to ride 17 miles. 

Hope this helps
5 0
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What is the distance from an arbitrary point (x,y) in ℝ2R2 to the x-axis?
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6 0
4 years ago
HELP NEEDED ASAP.....NO LINKS AND NO TROLLING
sveticcg [70]

Answer: I won't bother explaining cause you only want the answer

Step-by-step explanation:

page 1
Shift: a type of translation that moves the graph without changing its scale or shape or direction.

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page 2 (right to left in rows)

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y, subtracts

x, adds

x, subtracts

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8 0
3 years ago
A 39-foot ladder is leaning against a vertical wall. If the bottom of the ladder is being pulled away from the wall at the rate
LenaWriter [7]

Answer:

The area of the triangle formed is increasing at a rate of 29.75 square feet per second.

Step-by-step explanation:

A 39-foot ladder is leaning against a vertical wall. We are given that the bottom of the ladder is being pulled away at a rate of two feet per second, and we want to find the rate at which the area of the triangle being formed is is changing when the bottom of the ladder is 15 feet from the wall.

Please refer to the diagram below. <em>x</em> is the distance from the bottom of the ladder to the wall and <em>y</em> is the height of the ladder on the wall.

According to the Pythagorean Theorem:

\displaystyle x^2+y^2=1521

Let's take the derivative of both sides with respect to time <em>t</em>. Hence:

\displaystyle \frac{d}{dt}\left[x^2+y^2\right] = \frac{d}{dt}\left[ 1521\right]

Implicitly differentiate:

\displaystyle 2x\frac{dx}{dt} + 2y\frac{dy}{dt} = 0

Simplify:

\displaystyle x\frac{dx}{dt} + y \frac{dy}{dt} = 0

The area of the triangle formed will be given by:

\displaystyle A  = \frac{1}{2} xy

Again, let's take the derivative of both sides with respect to time <em>t: </em>

<em />\displaystyle \frac{dA}{dt} = \frac{d}{dt}\left[\frac{1}{2}xy\right]<em />

From the Product Rule:

\displaystyle \frac{dA}{dt} = \frac{1}{2}\left(y\frac{dx}{dt} + x\frac{dy}{dt}\right)

At that instant, the ladder is 15 feet from the base of the wall. So, <em>x</em> = 15. Using this information, find <em>y</em>.

\displaystyle y = \sqrt{1521-(15)^2}=36

The bottom of the ladder is being pulled away from the wall at a rate of two feet per second. So, dx/dt = 2. Using this information and the first equation, find dy/dt:

\displaystyle \frac{dy}{dt} =-\frac{x\dfrac{dx}{dt}}{y}

Evaluate for dy/dt:

\displaystyle \frac{dy}{dt} = -\frac{(15)(2)}{(36)}=-\frac{5}{6}

Finally, using dA/dt, substitute in appropriate values:

\displaystyle \frac{dA}{dt} = \frac{1}{2}\left((36)(2)+(15)\left(-\frac{5}{6}\right)\right)

Evaluate. Hence:

\displaystyle \frac{dA}{dt} = \frac{119\text{ ft}^2}{4\text{ s}} = 29.75\text{ ft$^2$/s}

The area of the triangle formed is increasing at a rate of 29.75 square feet per second.

8 0
3 years ago
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