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Advocard [28]
3 years ago
10

the mean height of a group of 500 nonsmoking college students is 74 inches and the standard deviation is 5 inches. what is the p

robability that in a random sample of 25 students from this group, the average height will be between 73 and 75 inches?
Mathematics
1 answer:
Novosadov [1.4K]3 years ago
3 0
Based on the given description above, I have analyzed it and come up with a solution to get the probability if in a random sample of 25 students from this said group and the average height is between 73 and 75 inches. So if you calculate it, it will be like this: 
<span>2P(Z<2)−1</span> To find the probability of Z, use the normal distribution table.
The value for Z being less than 2 is 0.9772. The final result is then<span><span>2(0.9772)−1=0.9544
Hope this is the answer that you are looking for.</span></span>
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Using a common denominator to order fractions, please help fast...
marshall27 [118]
3/10=15/50 and then 8/25=16/50

So, 3/10<8/25
5 0
3 years ago
HELP!
Alexxx [7]

Answer:

LIMIT

The policy will pay for up to

$100,000 of damage to

another person's property.

The policy will pay only

$100 per incident for a

tow truck

DEDUCTIBLE

The policyholder must pay

the first $1,000 of repair

expenses before insurance

will pay for anything,

PREMIUM

The policy offers coverage

for a cost of $178 per month

The policyholder must

pay $500 semiannually

to the insurance provider

Step-by-step explanation:

LIMIT is the maximum amount an insurer will pay toward a covered claim

DEDUCTIBLE is the amount paid out of pocket toward a covered claim

PREMIUM is the amount paid regularly to keep the policy in force.

6 0
3 years ago
What is the answer? help me
puteri [66]
The answer that I would choose would be C.
5 0
2 years ago
2.
laiz [17]

Answer:

B) 0.02

Step-by-step explanation:

<u>Use the Binomial Theorem</u>

\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=4)=\binom{30}{4}(0.30)^4(1-0.30)^{30-4}\\\\P(X=4)=\frac{30!}{4!(30-4)!}(0.30)^4(0.70)^{26}\\ \\P(X=4)=\frac{30!}{4!(26)!}(0.30)^4(0.70)^{26}\\ \\P(X=4)=\frac{30*29*28*27}{4*3*2*1}(0.30)^4(0.70)^{26}\\ \\P(X=4)=27405(0.30)^4(0.70)^{26}\\\\P(X=4)\approx0.0208

We have the probability of success, p=0.30, and the probability of failure, q=1-0.30=0.70. The binomial coefficient, \binom{n}{k}, represents the amount of possible combinations that k items can be chosen out of n items, with its respective formula \frac{n!}{k!(n-k)!}.

Hence, the best choice for the probability that 4 students chosen at random from the class of 30 that want the next test to be on Monday will be option B, 0.02

7 0
2 years ago
How many roots does this has?<br>x^2+(2√5x)+2x=-10​<br>find Discriminant
Alexxandr [17]

Given:

The equation is

x^2+(2\sqrt{5})+2x=-10

To find:

The number of roots and discriminant of the given equation.

Solution:

We have,

x^2+(2\sqrt{5})x+2x=-10

The highest degree of given equation is 2. So, the number of roots is also 2.

It can be written as

x^2+(2\sqrt{5}+2)x+10=0

Here, a=1, b=(2\sqrt{5}+2), c=10.

Discriminant of the given equation is

D=b^2-4ac

D=(2\sqrt{5}+2)^2-4(1)(10)

D=20+8\sqrt{5}+4-40

D=8\sqrt{5}-16

D\approx 1.89>0

Since discriminant is 8\sqrt{5}-16\approx 1.89, which is greater than 0, therefore, the given equation has two distinct real roots.

3 0
3 years ago
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