Answer:
See explanations below
Step-by-step explanation:
Given the functions f(x)=2x+3 and g(x)=x^2-1
a. Find f(g(x))
f(g(x)) = f(x^2-1)
f(g(x)) = 2(x^2-1)+3
f(g(x))= 2x^2-2+3
f(g(x)) = 2x^2+1
Hence the composite function f(g(x)) is 2x^2+1
b) g(f(x)) = g(2x+3)
g(f(x) = (2x+3)^2-1
g(f(x)) = 4x^2+12x+9-1
g(f(x)) = 4x^2+12x+8
The answer you are looking for is 50h+25
Hope that this helps!
Answer:
n² p²r³
Step-by-step explanation:
n ⋅ n ⋅ p ⋅ p ⋅ r ⋅ r ⋅ r
Write using exponents
There are 2 n terms
n²⋅ p ⋅ p ⋅ r ⋅ r ⋅ r
There are 2 p terms
n² p²⋅ r ⋅ r ⋅ r
There are 3 r terms
n² p²r³
Answer: Option C.
Step-by-step explanation:
The data is:
Destin walked 2km
Jane walked 4000ft.
Let's write both of those in the same units.
The data given is:
1ft = 0.0003048km.
and 4000ft is 4000 times that:
4000ft = 4000*1ft = 4000*0.0003048km = 1.22km
Then if we add those, we get:
Total distance = 2km + 1.22km = 3.22km
So we can already discard option D.
Now, we know that:
1km = 0.6214 miles.
then 3.22 km is 3.22 times that amount:
3.22km = 3.22*1km = 3.22*(0.6214 mi) = 2 miles
The correct option is C.
