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2 years ago

Find the area of the SHADED region.

Mathematics

1 answer:

7nadin3 [17]2 years ago

6 0

Split the shape into two shapes

A square

Area = L x H = 20 x 21 = 240 cm2

A right angle triangle

Area of right angle triangle = L x H divided by 2

20 x 21 = 240 divided by 2 = 120 cm2

Add both areas

240 + 120 = 360 cm2

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Math swatch pls help

solniwko [45]

Answer:

The answer is 11.9cm

Step-by-step explanation:

The solution is in the image

4 0

1 year ago

The formula for the perimeter of a rectangle is 2l + 2w, where l is the length and width. How can you use the Distributive Prope

Ann [662]

Try to find the common factor which is 2.
So:
Multiply by 2 both variables in parenthesis and you get:
2*(l+w)

5 0

2 years ago

Which is less 2.5 or -2.5? Answer asap pls!

masha68 [24]

its definitely -2.5........

4 0

3 years ago

Two passenger train, A and B, 450 km apart, star to move toward each other at the same time and meet after 2hours.

likoan [24]

Let $v$ be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are

$\begin{cases}s_A(t) = vt\\s_B(t) = -\dfrac{8}{7}vt+450\end{cases}$

where $s_A,\ s_B$ are the positions of trains A and B respectively, and t is the time in hours.

The two trains meet if and only if $s_A=s_B$ , and we know that this happens after two hours, i.e. at $t=2$

$\begin{cases}s_A(2) = 2v\\s_B(2) = -\dfrac{16}{7}v+450\end{cases}\implies 2v = -\dfrac{16}{7}v+450$

Solving this equation for v we have

$2v = -\dfrac{16}{7}v+450 \iff \dfrac{30}{7}v=450 \iff v=\dfrac{450\cdot 7}{30} = 105$

So, train A is travelling at 105 km/h. This implies that train B travels at

$105\cdot \dfrac{8}{7} = 15\cdot 8=120 \text{ km/h}$

5 0

2 years ago

Solve the inequality<br> 4b−4≤−20

devlian [24]

Answer:

b ≤ -4

Step-by-step explanation:

4b−4≤−20

4b - 4 + 4 ≤ - 20 + 4

4b ≤ -16

Divide both sides by 4

b ≤ -4

8 0

2 years ago